20 can be divided by 2 twice, with 5 remaining
20 can be divided by 4 once, with 5 remaining
20 can be divided by 5 once, with 4 remaining
20 can be divided by 10 twice
20 can be divided by 20 once
hope this helps
Answer:
x = 2 x = -6
Step-by-step explanation:
2 (x+2) ^2-4=28
Add 4 to each side
2 (x+2) ^2-4+4=28+4
2 (x+2) ^2= 32
Divide by 2
2/2 (x+2) ^2=32/2
(x+2)^2 = 16
Take the square root of each side
sqrt((x+2)^2) =±sqrt( 16)
x+2 = ±4
Subtract 2 from each side
x+2-2 = -2±4
x = -2±4
x = -2+4 and x = -2-4
x = 2 x = -6
8% of what number is 2 - 268832
W=2L-3
W*L=193
replace W with 2L-3: (2L-3)L=193
2L^2-3L-193=0
Cannot factor
are you sure the numbers are correct?
If it cannot be factored, use the quadratic formula to find out L, then you can find out W
use the Pythagorean theorem to find the diagonal. I don't see an easier way.
