1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ValentinkaMS [17]
2 years ago
5

(6 to the power of 3 times 3 to the power of 3) to the power of 2

Mathematics
1 answer:
frosja888 [35]2 years ago
4 0

Answer:

True

Step-by-step explanation:

(6³ * 3³)² = 18⁶

Multiply inside the parenthesis.

(18³)² = 18⁶

When you put powers to powers, they multiply, eg:

(x³)⁴ = x³°⁴ = x¹²

18⁶ = 18⁶

True.

You might be interested in
Which expression is equal to 4 x 3 x 5?
kupik [55]

Answer:

60

Step-by-step explanation:

Step 1: Write expression

4 × 3 × 5

Step 2: Multiply

12 × 5

60

3 0
3 years ago
Read 2 more answers
I don’t know what to do
sergey [27]
20% of 15 is 12$, and tax is 5% so it comes out to 12.60$
The answer is B
4 0
3 years ago
Read 2 more answers
The principal amount, $5500, earns 3.75% interest compounded continuously.
Eva8 [605]

Answer:

a)

The function that represents the value of the account at any time, t

\:\:A=Pe^{rt}

b)

The total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 5,500.00 at a rate of 3.75% per year  compounded continuously  over 6 years is $ 6,887.77.

Step-by-step explanation:

a. Write the function that represents the value of the account at any time, t.

The function that represents the value of the account at any time, t

\:\:A=Pe^{rt}

where

A represents the Future Value

P represents the Principle (Initial Value)

r represents the Interest rate

t represents the time

b) What will the value be after 6 years?

Given

The principal amount  P = $5500

Annual Rate r = 3.75% = 3.75/100 = 0.0375

Time Period  t  = 6 years

To Determine:

The total amount A = ?

Using the formula

\:\:A=Pe^{rt}

substituting the values

A\:=\:5500\left(2.71828\right)^{\left(0.0375\right)\left(6\right)}

A=5500\cdot \:2.71828^{0.225}

A = $ 6,887.77 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 5,500.00 at a rate of 3.75% per year  compounded continuously  over 6 years is $ 6,887.77.

8 0
3 years ago
How much does 73 go into 39?
Deffense [45]
.53424657534246575342465753424658

6 0
3 years ago
A student must choose one of the subjects, art, geology, or psychology, as an elective. She is equally likely to choose art or p
labwork [276]

Answer:

P (arts) = 0.25

P (psychology) = 0.25

P (geology) = 0.5

Step-by-step explanation:

Let the probability of choosing art = x

As given that she is equally likely to choose art or psychology and twice as likely to choose geology.

So,

P (arts) = x = P (psychology)

P (geology) = 2x

The sum of the probability = 1

So,

P (arts) + (psychology) + P (geology) = 1

x + x + 2x = 1

<u>x = 0.25</u>

<u>P (arts) = x = 0.25</u>

<u>P (psychology) = x = 0.25</u>

<u>P (geology) = 2x = 2*0.25 = 0.5</u>

5 0
3 years ago
Other questions:
  • Average Joe goes to a community college for an interview. He wants to train for a career with a lot of openings. One career they
    15·1 answer
  • The line of best fit drawn on a scatter plot ____
    12·2 answers
  • What is the length of the side jk
    10·1 answer
  • FIRST ONE TO ANSWER GETS BRAINLIST
    12·2 answers
  • What is (0.64) • (0.81)?
    12·2 answers
  • Lillian rides her bike a distance of 20 to 30 miles each day.Estimate the total number of miles she will ride her bike in 4 days
    6·1 answer
  • How to graph y=55x+100
    14·1 answer
  • What are the solutions of the equation? x² – 21 = –4x
    8·2 answers
  • Which describes the cross section of the cube that passes through the vertices A, B, and C shown below?
    9·2 answers
  • HELP PLZZZ !! <br><br> 3. Solve the equation by factoring.<br> C^2 - 4c = 0
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!