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Paraphin [41]
3 years ago
15

Teresa is maintaining a camp fire. She can keep the fire burning for 4 hours with 6 logs. she wants to know how many logs she ne

eds to keep the fire burning for 18 hours. she assumes all logs are the same.
Mathematics
2 answers:
Leya [2.2K]3 years ago
8 0

Answer:

Teresa will need 27 logs to keep the fire going for 18 hours.

Step-by-step explanation:

Teresa can keep the firing going for four hours with six logs. We can therefore determine the amount of logs is needed per hour:

amount of logs needed per hour =6/4=1.5 so we need 1.5 logs/hour to keep the fire going.

If Teresa wants to keep the fire going for 18 hours we can determine this by multiply the 18 hours by the logs per hour rate:

Logs needed for 18 hours of burning a camp fire

=18*1.5=27

Therefore she will need 27 logs to keep the fire going for 18 hours.

balandron [24]3 years ago
7 0
To keep the fire burning for 18 hours, she needs 18/4 times 6=27 logs.
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Answer:

Let u=3x^2-3x

Solution: \frac{1}{6} \sqrt{3x^2-3x}+C

Step-by-step explanation:

See attached for step-by-step

8 0
3 years ago
Please right answer for 25 pts and a mark. A store is having a sale on chocolate chips and walnuts. For 3 pounds of chocolate ch
Alexxandr [17]

Answer:

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3 0
3 years ago
SampleVarianceandStandardError: You encounter a deck of Martian playing cards.There are 87 cards in the deck. You cannot read Ma
docker41 [41]

Answer:

(a) The standard error of estimate of the fraction of blue cards in the deck is 0.145.

(b) The sample size required is 84.

Step-by-step explanation:

The proportion of blue cards is, <em>p</em> = 0.30.

The number of times the cards were shuffled is, <em>n</em> = 10.

(a)

The standard error for sample proportion is given by:

SE_{p}=\sqrt{\frac{p(1-p)}{n}}

Compute the value of standard error as follows:

SE_{p}=\sqrt{\frac{p(1-p)}{n}}\\=\sqrt{\frac{0.30\times (1-0.30)}{10}}\\=\sqrt{0.021}\\=0.145

Thus, the standard error of estimate of the fraction of blue cards in the deck is 0.145.

(b)

Now we need to reduce the standard error.

The standard error is inversely proportional to the sample size.

If the sample size is increased then the standard error will be decreased.

So we need to use a larger sample size.

Compute the value of <em>n</em> for standard error 0.05 and <em>p</em> = 0.30 as follows:

SE_{p}=\sqrt{\frac{p(1-p)}{n}}\\0.05=\sqrt{\frac{0.30(1-0.30)}{n}}\\0.05^{2}=\frac{0.21}{n}\\n=84

Thus, the sample size required is 84.

4 0
4 years ago
Gas costs $1.64 a gallon. Elaine spent $23.78 at the gas station.How many gallons of gas did she but?
EleoNora [17]
$1.64 per gallon
she paid $23.78
23.78÷1.64
She paid for <span>14.5 gallons

To check:
1.64 * 14.5 </span>
<span>23.78

Hope this helps</span>
8 0
4 years ago
Dean Halverson recently read that full-time college students study 20 hours each week. She decides to do a study at her universi
romanna [79]

Answer: The p-value is 0.154.

Step-by-step explanation:

Since we have given that

We claim that

Null hypothesis :

H_0:\mu=20

Alternate hypothesis :

H_1:\mu

Population mean = 20 hours

Sample mean = 18.5 hours

Sample standard deviation = 4.3 hours

Sample size n = 35

So, test statistic would be

z=\dfrac{\bar{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\\\\z=\dfrac{18.5-20}{\dfrac{4.3}{\sqrt{35}}}\\\\z=\dfrac{-1.5}{0.726}\\\\z=-2.066

So, the  p value would be 0.154.

Hence, the p-value is 0.154.

4 0
4 years ago
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