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3 years ago

PLEASE HELP ANSWER THISS!!! I NEED THIS PLEASE!!! AND NO LINKS EITHER PLSS!!

Mathematics

1 answer:

Sophie [7]3 years ago

6 0

It doesn't change because to add fractions, you need a common denominator. To find it, they multiplied 1/3 by 2 to make 2/6, to add to the 3/6.

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Which operation properly transforms matrix I to matrix II?

Y_Kistochka [10]

Answer:

Step-by-step explanation:

Replace R1 with 1 and R3 with 0 you have -2(1)+0 which equals 0 and that matches matrix II. Repeat the process with the other numbers in R1 and R3 and they all come out equal therefor the answer is D.

8 0

3 years ago

A daycare charges $115 per week for one child. Each additional child costs $65 for the week. If a family pays $505 for a week, h

valentinak56 [21]

Answer:

7 children

Step-by-step explanation:

$505-$115= $390

$390÷$65= 6

6+1= 7

4 0

3 years ago

An industry representative claims that 10 percent of all satellite dish owners subscribe to at least one premium movie channel.

Greeley [361]

Answer: 1) 0.6561 2) 0.0037

Step-by-step explanation:

We use Binomial distribution here , where the probability of getting x success in n trials is given by :-

$P(X=x)=^nC_xp^x(1-p)^{n-x}$

, where p =Probability of getting success in each trial.

As per given , we have

The probability that any satellite dish owners subscribe to at least one premium movie channel. : p=0.10

Sample size : n= 4

Let x denotes the number of dish owners in the sample subscribes to at least one premium movie channel.

1) The probability that none of the dish owners in the sample subscribes to at least one premium movie channel = $P(X=0)=^4C_0(0.10)^0(1-0.10)^{4}$

$=(1)(0.90)^4=0.6561$

∴ The probability that none of the dish owners in the sample subscribes to at least one premium movie channel is 0.6561.

2) The probability that more than two dish owners in the sample subscribe to at least one premium movie channel.

= $P(X>2)=1-P(X\leq2)\\\\=1-[P(X=0)+P(X=1)+P(X=2)]\\\\= 1-[0.6561+^4C_1(0.10)^1(0.90)^{3}+^4C_2(0.10)^2(0.90)^{2}]\\\\=1-[0.6561+(4)(0.0729)+\dfrac{4!}{2!2!}(0.0081)]\\\\=1-[0.6561+0.2916+0.0486]\\\\=1-0.9963=0.0037$

∴ The probability that more than two dish owners in the sample subscribe to at least one premium movie channel is 0.0037.

8 0

3 years ago

Liwen and Celina shared some plants in a ratio of 5:6. Celina decided to give Liwen 2/3 of her plants, which left her with 21 fe

djyliett [7]

Answer: 231

Explanation:

Liwen Celina

5x 6x

5x - 21 = $(\frac{2}{3})$ 6x

5x - 21 = 4x

-4x +21 -4x +21

x = 21

Liwen: 5x = 5(21) = 105

Celina: 6x = 6(21) = 126

Total: 231

6 0

3 years ago

Choose the correct description of the graph of the inequality x - 3s 5.

padilas [110]

Answer:

x - 3 > = 5

x > = 5 + 3

x > = 8

closed circle on 8...because of the equal sign.....shaded to the right...because of the > sign.

Step-by-step explanation:

6 0

3 years ago