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3 years ago

Write the products of photosystem i and photosystem ii

Chemistry

2 answers:

lisabon 2012 [21]3 years ago

8 0

Answer:

Explanation:

Photosystems are generally involved in photosynthesis, they assist in carrying out basic photochemistry (absorption of light and transfer of energy) during photosynthesis.

Photosystem I (or PSI) produces high energy compounds; ATP and NADPH from light energy absorbed during the light reactions of photosynthesis in algae, plants and some bacteria.

Photosystem II is the first membrane protein complex in organisms that produce oxygen. This oxygen oxidizes two molecules of water (in the presence of light) to produce molecular oxygen.

Margaret [11]3 years ago

3 0

ATP,O2 and NADPH are the products. H2O,NADP,ADP and Pi are the reactants. acts as an electron carrier between the cytochrome b6f and photosystem 1 (PS1) complexes in the photosynthetic electron-transfer chain.

Photosystem II (or water-plastoquinone oxidoreductase) is the first protein complex in the light-dependent reactions of oxygenic photosynthesis. It is located in the thylakoid membrane of plants, algae, and cyanobacteria.

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According to each substances heat of fusion, which of the items below requires more heat to be added per gram of substance to go

alexira [117]

Answer: The correct answer is Silver.

Explanation:

Specific heat of fusion is defined as the amount of heat which is required to raise the temperature of 1 gram of a substance to 1°C. It is generally expressed in kJ/mol

We are required to find the substance which require more heat. For that we need to know the specific heat of all the substances.

The substance which have the highest specific heat, will require more heat.

The specific heat of the given substances are:

Silver = 11.3 kJ/mol

Sulfur = 1.7175 kJ/mol

Water = 5.98 kJ/mol

Lead = 4.799 kJ/mol

The specific heat of silver is the highest and hence, will require more heat.

Hence, the correct answer is silver.

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3 years ago

When you light a fireplace what energy transformation occurs?

snow_tiger [21]

thermal energy

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3 years ago

To what volume in millimeters must 50.0 mL of 18.0 M H2SO4 be diluted to obtain 4.35 M H2SO4?

poizon [28]

We know that to relate solutions of with the factors of molarity and volume, we can use the equation: $M_{1} V_{1} = M_{2} V_{2}$

**NOTE: The volume as indicated in this question is defined in L, not mL, so that conversion must be made. However it is 1000 mL = 1 L.

So now we can assign values to these variables. Let us say that the 18 M $H_{2} SO_{4}$ is the left side of the equation. Then we have:

$(18 M)(0.050 L)=(4.35M) V_{2}$

We can then solve for $V_{2}$ :

$V_{2}= \frac{(18M)(0.05L)}{4.35M}$ and $V_{2} =0.21 L$ or $210 mL$

We now know that the total amount of volume of the 4.35 M solution will be 210 mL. This is assuming that the entirety of the 50 mL of 18 M is used and the rest (160 mL) of water is then added.

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3 years ago

What is the freezing point of a solution made with 1.31 mol of CHCl3 in 530.0 g of CCl4 (Kf =29.8 degrees C/m, Freezing point of

Allisa [31]

73.606 °C is the freezing point of the solution made with with 1.31 mol of CHCl3 in 530.0 g of CCl4.

Explanation:

Data given:

number of moles of CHCl3 = 1.31 moles

mass of solvent CHCl3 = 530 grams or 0.53 kg

Kf = 29.8 degrees C/m

freezing point of pure solvent or CCl4 = -22.9 degrees

freezing point = ?

The formula used to calculate the freezing point of the mixture is

ΔT = iKf.m

m= molality

molality = $\frac{moles of solute}{mass of solvent in kilograms}$

putting the value in the equation:

molality= $\frac{1.31}{0.53}$

= 2.47 M

Putting the values in freezing point equation

ΔT = 1.31 x 29.8 x 2.47

ΔT = 73.606 degrees

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3 years ago

During the action of a sodium-potassium pump, 50 ATP molecules were spent. Predict how many sodium ions are transported across t

larisa [96]

Yes, each ATP molecule aids in moving 3 Na+ across the membrane.
so 150 sodium ions are transported across the cell membrane when 50 ATP molecules are spent.

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3 years ago