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Keith_Richards [23]

3 years ago

11

Your favorite beach has 42 large sand dunes throughout the course of the year wind erosion destroys eight sand dunes and create

new ones how many sand dunes would there be the end of the year

1 answer:

a_sh-v [17]3 years ago

8 0

42- 8 = 34 sand dunes must be the answer

hope so it helps

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Which of the following statements related to S N1 reactions is not true? - The heterolysis of a bond between atoms which do not

Varvara68 [4.7K]

Answer:

The charged carbon atom of a carbocation has a complete octet of valence shell electrons

Explanation:

A charged carbon atom of a carbocation has a valence shell that is not filled, <u>that's why it acts as an electrophile (or a Lewis base)</u>. This unfilled valence shell is also the reason of the nucleophilic attack that takes place during the second step of a SN1 reaction.

6 0

3 years ago

Put the level of organization in order from smallest to largest a. Organelles, cellsorgans, tissuesorgan systems b. Organs, tiss

Lesechka [4]

Answer: My guess is D i hope this is right

Explanation:

8 0

3 years ago

How many milliliters of 2.19 M H2SO4 are required to react with 4.75 g of solid containing 21.6 wt% Ba(NO3)2 if the reaction is

Setler [38]

Answer:

1.7927 mL

Explanation:

The mass of solid taken = 4.75 g

This solid contains 21.6 wt% $Ba(NO_3)_2$ , thus,

Mass of $Ba(NO_3)_2$ = $\frac {21.6}{100}\times 4.75\ g$ = 1.026 g

Molar mass of $Ba(NO_3)_2$ = 261.337 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{1.026\ g}{261.337\ g/mol}$

$Moles= 0.003926\ mol$

Considering the reaction as:

$Ba(NO_3)_2+H_2SO_4\rightarrow BaSO_4+2HNO_3$

1 moles of $Ba(NO_3)_2$ react with 1 mole of $H_2SO_4$

Thus,

0.003926 mole of $Ba(NO_3)_2$ react with 0.003926 mole of $H_2SO_4$

Moles of $H_2SO_4$ = 0.003926 mole

Also, considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

Molarity = 2.19 M

So,

$2.19=\frac{0.003926}{Volume\ of\ the\ solution(L)}$

Volume = 0.0017927 L

Also, 1 L = 1000 mL

<u>So, volume = 1.7927 mL</u>

5 0

3 years ago

You have 7.86 x 10^23 molecules of NaCl. This would be equal to ___ grams of NaCl.

sergij07 [2.7K]

$7.86 \times 10 {}^{23} atoms \\ \frac{7.86}{6.022} \times \frac{10 {}^{23} }{ {10}^{23} } = 1.305\: moles$

1.305 × (23+35.5) = 76.34 grams

3 0

3 years ago

Carbon + oxygen --><br> carbon dioxide<br> balancing equation

vaieri [72.5K]

Carbon = C

Oxygen = O

CO2 = Carbondioxide

Balanced equation :

C + O2 = CO2

8 0

3 years ago

Read 2 more answers