If magnesium and nickel were used as electrodes to construct an electrochemical cell like the one shown at right, which metal wo
uld form the anode and which the cathode?
anode:
cathode:
anode:
cathode:
1 answer:
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Answer:- Atomic number for sulfur is 16 and it's electron configuration is . Here, there are total for electrons in 3p and the set of quantum numbers for these 4 electrons would be as..
For the first electron of 3p-
n = 3, l = 1, ml = -1 and ms = +(1/2)
for the second electron of 3p-
n = 3, l = 1, ml = 0 and ms = +(1/2)
for the third electron of 3p-
n = 3, l = 1, ml = +1 and ms = +(1/2)
and for the fourth electron of 3p-
n = 3, l = 1, ml = -1 and ms = -(1/2)
Answer : 0.0392 grams of Zn metal would be required to completely reduced the vanadium.
Explanation :
Let us rewrite the given equations again.
On adding above equations, we get the following combined equation.
We have 12.1 mL of 0.033 M solution of VO₂⁺.
Let us find the moles of VO₂⁺ from this information.
From the combined equation, we can see that the mole ratio of VO₂⁺ to Zn is 2:3.
Let us use this as a conversion factor to find the moles of Zn.
Let us convert the moles of Zn to grams of Zn using molar mass of Zn.
Molar mass of Zn is 65.38 g/mol.
We need 0.0392 grams of Zn metal to completely reduce vanadium.