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const2013 [10]
3 years ago
13

Please someone solve this and tell me how you solve it

Chemistry
1 answer:
lianna [129]3 years ago
8 0

Answer:

Supersaturated.

Explanation:

Hello there!

In this case, according to this solubility chart, we infer that for NH3, the solubility starts at 90 grams of NH3 that are soluble in 100 g of water at 0 °C and ends in about 8 g in 100 g of water at 100 °C for a saturated solution.

However, since we are asked for the solubility of NH3 at 20 °C, we can see that, according to the table and the curve for NH3, about 52 g of NH3 are soluble in 100 g of water; thus, for the given 60 g of NH3, we will say that 8 grams will remain undissolved, and therefore, this solution will be supersaturated.

Regards!

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(a) 4.64 x 1024 atoms Bi into grams
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1610.7 g is the weigh for 4.64×10²⁴ atoms of Bi

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Let's do the required conversions:

1 mol of atoms has 6.02×10²³ atoms

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Let's do the rules of three:

6.02×10²³ atoms are the amount of 1 mol of Bi

4.64×10²⁴ atoms are contained in (4.64×10²⁴ . 1) /6.02×10²³ = 7.71 moles

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7.71 moles of Bi must weigh (7.71 . 208.98 ) /1 = 1610.7 g

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