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3 years ago

Solve for "n"! 3(n+4)=-6+15n help ASAP RANDOM ANSWERS WILL BE MODERATED!

1 answer:

amm18123 years ago

4 0

We are told to solve for n given the equation 3(n + 4) = -6 + 15n. We can solve for n by first using the distributive property, which gives us 3n + 12 = -6 + 15n. Now, subtract 15n from both sides, giving us -12n + 12 = -6. Next, subtract 12 from both sides to get -12n = -18. Now, divide both sides by -12 to get n = 18/12, or 3/2 when simplified. Therefore, the value of n in the equation 3(n + 4) = -6 + 15n is 3/2. Hope this helped!

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Morgarella [4.7K]

Answer:

55,784 oranges

Step-by-step explanation:

To fill the vats, they would need the number of oranges needed to fill one vat multiplied by the amount of vats they have.

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A student earned a grade of 80% on a math test that had 20 problems. How many problems on this test did the student answer corre

boyakko [2]

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I need help please and thank you

STatiana [176]

Answer:

∠A = 45°

Step-by-step explanation:

The sum of angles in a triangle = 180°.

That means in the triangle ABC, ∠A + ∠B + ∠C = 180°.

Given ∠B = 90° and ∠C = 45°.

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3 years ago

The prices of commodities X,Y,Z are respectively x, y, z, rupees per unit. Mr. A purchases 4 units of Z and sells 3 units of X a

liubo4ka [24]

Answer:

$(x,y,z)=(1477, 1464, 1437)$

Step-by-step explanation:

Consider the selling of the units positive earning and the purchasing of the units negative earning.

Mr. A purchases 4 units of Z and sells 3 units of X and 5 units of Y
Mr.A earns Rs6000

So, the equation would be

$3x + 5y - 4z = 6000$

Mr. B purchases 3 units of Y and sells 2 units of X and 1 units of Z
Mr B neither lose nor gain meaning he has made 0₹

hence,

$2x - 3y + z = 0$

Mr. C purchases 1 units of X and sells 4 units of Y and 6 units of Z
Mr.C earns 13000₹

therefore,

$- x + 4y + 6z = 13000$

Thus our system of equations is

$\begin{cases}3x + 5y - 4z = 6000\\2x - 3y + z = 0\\ - x + 4y + 6z = 13000\end{cases}$

<u>Solving </u><u>the </u><u>system </u><u>of </u><u>equations</u><u>:</u>

we will consider elimination method to solve the system of equations. To do so ,separate the equation in two parts which yields:

$\begin{cases}3x + 5y - 4z = 6000\\2x - 3y + z = 0\end{cases}\\\begin{cases}2x - 3y + z = 0\\ - x + 4y + 6z = 13000\end{cases}$

Now solve the equation accordingly:

$\implies\begin{cases}11x-7y=6000\\-13x+22y=13000\end{cases}$

Solving the equation for x and y yields:

$\implies\begin{cases}x= \dfrac{223000}{151}\\\\y= \dfrac{221000}{151}\end{cases}$

plug in the value of x and y into 2x - 3y + z = 0 and simplify to get z. hence,

$\implies z= \dfrac{217000}{151}$

Therefore,the prices of commodities X,Y,Z are respectively approximately 1477, 1464, 1437

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2 years ago