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barxatty [35]
3 years ago
6

Felicia invested money at an interest rate of 4%. After six months, she had earned $90.00 interest. How much money did Felicia i

nvest?
I = prt
90 = p(0.04)(0.5)
90 = p(0.02)
p = _________ dollars
Mathematics
2 answers:
WARRIOR [948]3 years ago
8 0
The formula is
I=prt
I interest earned 90
P amount invested? 
R interest rate 0.04
T time 6/12
Solve the formula for p
P=I÷rt
P=90÷(0.04×(6÷12))
P=4,500 ....answer
Paul [167]3 years ago
4 0

Answer:

The formula is

I=prt

I interest earned 90

P amount invested?

R interest rate 0.04

T time 6/12

Solve the formula for p

P=I÷rt

P=90÷(0.04×(6÷12))

P=4,500 ....answer

Step-by-step explanation:

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90-29.6=60.4 degrees

Hope this helps!

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The question is in the screenshot
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Answer:

b. -36/77

Step-by-step explanation:

As 0 < x < \pi/2 => tan x > 0

As 0< y <  \pi/2 => tan y > 0

We have the formula:

  • \frac{1}{sin^{2}x } =1 + cot^{2}x => \frac{1}{(8/17)^{2} } = 1+cot^{2}x => cot^{2} x=225/64

As tan x = 1/(cotx) => tan^{2}x = \frac{1}{cot^{2}x} =\frac{1}{225/64} = \frac{64}{225}

As tan x > 0 => tan x = 8/15

  • \frac{1}{cos^{2}y } = 1+tan^{2}y => \frac{1}{(3/5)^{2} } = 1 + tan^{2} y => tan^{2}y=\frac{16}{9}

As tan y > 0 => tan y = 4/3

As tan (x-y)= \frac{tan x - tan y}{1+ tanx * tany} =\frac{(8/15)-(4/3)}{1+(8/15)*(4/3)} = \frac{-36}{77}  

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Read 2 more answers
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