Josiah and Chana travel at constant and different speeds.
- The point F indicates that after 25 seconds Josiah is 60 meters from the starting line but behind Chana
<h3>How can the what the the point <em>F </em>represent be known?</h3>
Josiah's head start = 10 meters from the start
Josiah's speed = 2 m/s
Chana's speed = 3 m/s
Expressing the distance traveled as an equation, we have;
D = d + s × t
Where;
D = The distance covered
d = The distance from the starting line the runner starts
s = The speed of the runner
t = The time spent running
For Josiah, we have;
D = 10 + 2•t (line <em>a</em>)
For Chana, we have;
D = 0 + 3•t = 3•t (line <em>b</em>)
The above equations are straight line equations.
The point <em>F </em>is on line <em>a</em>, which shows Josiah distance after 25 seconds which is 60 meters. The corresponding point on line <em>b</em>, Chana's distance after 25 minutes is 75 meters.
Therefore;
- The point <em>F </em>indicates that after 25 seconds Josiah is 60 meters from the starting line but behind Chana
Learn more about straight line equations here:
https://brainly.in/question/16254550
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Answer:
X = 6°
Step-by-step explanation:
In a set of parallel lines, the opposite angles and corresponding angles are similar. Since the opposite angle of 110° is the corresponding angle of 19x - 4, you can conclude that 19x - 4 = 110° ⇒ 19x = 114° ⇒ x = 6°.
Answer:
12
Step-by-step explanation:
This can be solved by working backwards.
7 is one more than half the number of invitations.
Subtract 1. 6 is half the number of invitations.
Double.
12 is the full number of invitations.
Algebra (if you must!):
x = number of invitations
x/2 + 1 = 7
Subtract 1.
x/2 = 6
Multiply by 2.
x = 12
0.0000000861 is your answer
