Answer:
The answer is below
Explanation:
1.5 - kΩ resistor is connected to an AC voltage source with an rms voltage of 120 V. (a) What is the maximum voltage across the resistor? (b) What is the maximum current through the resistor? (c) What is the rms current through the resistor? d) What is the average power dissipated by the resistor?
Solution:
The rms value of current and voltage shows the alternating quantity of the voltage and current.
Given that V(rms) = 120 V, R = 1.5 kΩ
a) The maximum voltage across the resistor is given as:
b) The maximum current through the resistor is:
c) The rms current through the resistor is:
d) The average power dissipated by the resistor is:
B. +Q, + W are the correct sign
I'm assuming by the phrasing of your question that you are looking for examples of simple machines that are not wedges.
Well, there are five other simple machines. There is a pulley, lever, screw, wheel and axle, and an inclined plane.
Hope that helped you!
<span>B) 0.6 N
I suspect you have a minor error in your question. Claiming a coefficient of static friction of 0.30N is nonsensical. Putting the Newton there is incorrect. The figure of 0.25 for the coefficient of kinetic friction looks OK. So with that correction in mind, let's solve the problem.
The coefficient of static friction is the multiplier to apply to the normal force in order to start the object moving. And the coefficient of kinetic friction (which is usually smaller than the coefficient of static friction) is the multiplied to the normal force in order to keep the object moving. You've been given a normal force of 2N, so you need to multiply the coefficient of static friction by that in order to get the amount of force it takes to start the shoe moving. So:
0.30 * 2N = 0.6N
And if you look at your options, you'll see that option "B" matches exactly.</span>