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snow_tiger [21]
3 years ago
13

the wavelength produce by a shallow water body is 200mm. If the refractive index is 0.5. calculate the wavelength in deep water​

Physics
1 answer:
Delicious77 [7]3 years ago
6 0

Answer:

400mm

Explanation:

Refractive index is the ratio of the wavelength in the shallow water to that in deep water.

Refractive index = λs/λd

Given

Refractive index = 0.5

λs = 200mm

Required

0.5 = 200/λd

λd = 200/0.5

λd = 400mm

Hence the wavelength in deep water is 400mm

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Answer:

The speed of the potato at the lowest point is 6.714 m/s

The tension in the string is 8.82 N

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When the potato is at 2.30 m height, it will have potential energy and when  the potato released it will go lowest point and it's potential energy will be convert into kinetic energy.

                       Potential energy = Kinetic energy

                                  m×g×h      = (1/2) m×v²

m stands  for mass

g stands for gravitational constant

h stands for height

v stands for velocity

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                      0.3×9.8×2.3 = (1/2) .3×v²

                       v² = 45.08

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The speed of the potato at lowest point is 6.714 m/s

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 The potato is in uniform circular motion so the acceleration is given by

                          a = v² / r

a stands for centripetal acceleration

According to Newton second law the acceleration  is  directly proportional to applied force and inversely proportional to the mass of object

     So                     ∑ F = m × a

Two forces act on potato 1. weight due to gravitation in downward direction 2. tension in upward direction So the above equation become

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           centripetal acceleration formula =v²/r    ,   r = l = length of the string

                        T  = m ×(v²/l) + m×g

  v = 6.714 m/s ,  l = 2.30 m ,   m = .3 kg Now put values in above equation

                         T = .3 × (6.714²/2.30) + .3 × 9.8

                        T  = .3 ( 45.08/2.30) + 2.94

                        T  = .3 (19.6) +2.94

                        T  = 5.88 + 2.94

                        T  = 8.82 N

          The tension in the string is 8.82 N

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