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Viktor [21]
3 years ago
11

A large region of gas and dust that may contain as many as one million solar masses is called a _____.

Physics
2 answers:
dexar [7]3 years ago
6 0
The correct answer that would best complete the given statement above would be option B. PROTOSTAR. A large region of gas and dust that may contain as many as one million solar masses is called a protostar or star formation. Protostar is <span>a contracting mass of gas that represents an early stage in the formation of a star. Hope this helps.</span>
marshall27 [118]3 years ago
6 0

Answer:

a giant molecular cloud.

Explanation:

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The water hose at your home outputs 24 gallons of water a minute. how many cubic centimeters per second does the hose output? th
adoni [48]

When we convert 24 gallon/min to cubic centimeters per second (cm³/s), the result obtained is 1514.164 cm³/s

<h3>How to convert 24 gallon/min to cm³/min</h3>

We'll begin by converting 24 gallon/min to cm³/min. This can be obtained as follow:

1 gallon/min = 3785.41 cm³/min

Therefore,

24 gallon/min = (24 gallon/min × 3785.41 cm³/min) / 1 gallon/min

24 gallon/min = 90849.84 cm³/min

<h3>How to convert 90849.84 cm³/min to cm³/s</h3>

We can convert 90849.84 cm³/min to cm³/s as follow:

60 cm³/min = 1 cm³/s

Therefore,

90849.84 cm³/min = (90849.84 cm³/min × 1 cm³/s) / 60 cm³/min

90849.84 cm³/min = 1514.164 cm³/s

Thus,

24 gallon/min = 1514.164 cm³/s

Learn more about conversion:

brainly.com/question/2139943

#SPJ1

7 0
1 year ago
What force is needed to give a 4800.0 kg truck an acceleration of 6.2 m/s2 over a level road? ​
tekilochka [14]

Answer:

the force needed to give the truck the acceleration is 29,760 N.

Explanation:

Given;

mass of truck, m = 4800 kg

acceleration of the truck, a = 6.2 m/s²

The force needed to give the truck the acceleration is calculated as;

F = ma

F = 4800 x 6.2

F = 29,760 N

Therefore, the force needed to give the truck the acceleration is 29,760 N.

6 0
2 years ago
The froghopper, Philaenus spumarius, holds the world record for insect jumps. When leaping at an angle of 58.0 above the horizon
kirza4 [7]

Answer:

A) 3.79 m/s  B) 1.33 m

Explanation:

A)

  • Horizontal movement:
  • Once in the air, no forces act on the froghopper, so it keeps moving with the same initial horizontal speed.
  • This horizontal component, is the projection of the velocity vector on the horizontal direction (x-axis):

        v_{ox} = v_{o} *cos (58.0 deg)

  • The horizontal displacement can be simply calculated as follows:

        x = v_{ox} *t

  • Vertical movement:
  • As the vertical and horizontal are independent each other (due to they are perpendicular, so there is no projection of one movement on the other), in the vertical direction, all happens as if would be a body thrown upward with a given initial vertical velocity.
  • This velocity can be found as the projection of the velocity vector on the vertical direction (y-axis):

        v_{oy} = v_{o} *sin (58.0 deg) (1)

  • Once in the air, the gravity will cause that the froghopper be slow down, till it reaches to the maximum height, where it will come momentarily to an stop.
  • In that moment, we can apply the following kinematic equation:

        v_{fy} ^{2} -v_{oy} ^{2} = 2*g*h_{max}

  • where vfy = 0, g = -9.8m/s2, hmax = 52.7 cm= 0.527 m
  • Replacing by the givens, we can solve for voy:

        v_{oy} =\sqrt{2*g*h_{max}} = \sqrt{2*9.8m/s2*0.527m} =3.21 m/s

  • From the equation (1), we can solve for the magnitude of the initial velocity, v₀:

        v_{o} = \frac{v_{oy}}{sin 58.0} =\frac{3.21m/s}{0.848} = 3.79 m/s

B)

  • With the value of the magnitude of the initial velocity, we can find the horizontal component vox, as follows:

        v_{ox} = v_{o} *cos (58.0 deg) =\\  \\ 3.79 m/s * cos (58.0deg) = 2.01 m/s

  • In order to know the horizontal distance travelled, we need to find the time that the insect was in the air.
  • We can use the equation for the vertical displacement, replacing this value by 0, as follows:

       y = 0 = v_{oy} *t -\frac{1}{2} * g *t^{2}

  • Replacing by  the givens, and rearranging terms, we can solve for t:

        t_{air} =\frac{2*v_{oy} }{g} = \frac{2*3.21 m/s}{9.8 m/s} = 0.66 s

  • Finally, we find the horizontal displacement, as follows:

       x_{max}  = v_{ox} *t_{air} = 2.01 m/s * 0.66 s \\ \\ x_{max} = 1.33 m

  • The horizontal distance covered by  the froghopper was 1.33 m.
4 0
3 years ago
um ima em forma de barra atravessa uma espira retangular, como mostra a imagem. Sabendo que esse e um caso em que o fluxo magnet
SashulF [63]

Answer:De acuerdo con la ley de inducción electromagnética de Faraday, la tasa de cambio del flujo magnético vinculado con la bobina es directamente proporcional a la fem inducida en la bobina.

e = - d∅ / dt

Entonces, si el cambio de flujo es mayor, la fem inducida es mayor.

¡espero haber ayudado a tener un buen día! :)

Explanation:

 According to the Faraday's law of electromagnetic induction, the rate of change of magnetic flux linked with the coil is directly proportional to the induced emf in the coil.

e = - d∅ / dt

So, if the flux change is more the induced emf is more.

i hope i helped have a good day! :)

7 0
2 years ago
What is Si system? Why has Si system been developed? Give reason.​
patriot [66]

The International System of Units is the modern form of the metric system. It is the only system of measurement with an official status in nearly every country in the world. ..

SI <em>SYSTEM</em><em> </em><em>WAS</em><em> </em><em>DEVELOPED</em><em> </em><em>BECAUSE</em><em> </em>

It allows people in different places and different countries to use the same units, avoid mistakes and understand each other more easily. The common base 10 of all units makes it easier and has more accurate calculations that are made without cumbersome conversion factors.....

  • HOPE THIS WILL HELP U
  • AND PLZ MARK ME AS A BRAINLIEST....

8 0
2 years ago
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