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Alenkasestr [34]
4 years ago
15

When an object is at rest do forces act on it

Physics
1 answer:
konstantin123 [22]4 years ago
5 0

Maybe they do, and maybe they don't. Just being at rest doesn't tell us.

But we DO know that if there ARE forces acting on an object at rest, then they must be balanced. Otherwise the object would be accelerating.

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a wave having a wavelength of 4.7 meters and an amplitude of 2.5 meters travels a distance of 28 meters in 7 seconds. determine
Aleksandr [31]

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<h2>T(Period) = 1.33s</h2><h2>f(Frequency) = 0.75Hz (cycles/second)</h2>

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4 0
3 years ago
A container with volume 1.83 L is initially evacuated. Then it is filled with 0.246 g of N2. Assume that the pressure of the gas
alisha [4.7K]

Answer:

The  pressure is  P =   1652 \  Pa

Explanation:

From the question we are told that

    The  volume of the container is  V  =  1.83  \ L =  1.83 *10^{-3 } \  m^3

     The mass of  N_2 is  m_n  =  0.246 \ g =  0.246 *10^{-3} \ kg

     The root-mean-square velocity is  v =  192 \ m/s

The  root -mean square velocity is mathematically represented as

      v =  \sqrt{ \frac{3 RT}{M_n  } }

Now the ideal gas law is mathematically represented as

      PV  =  nRT

=>   RT  =  \frac{PV}{n }

Where n is the number of moles which is mathematically represented as

         n =  \frac{ m_n }{M }

Where  M  is the molar mass of  N_2

So  

        RT  =  \frac{PVM_n }{m _n  }

=>    v =  \sqrt{ \frac{3 \frac{P* V  *  M_n }{m_n } }{M_n  } }

=>    v =  \sqrt{  \frac{ 3 *  P* V  }{m_n } } }

=>   P =   \frac{v^2   *  m_n}{3 *    V  }

substituting values

    =>    P =   \frac{( 192)^2   *  0.246 *10^{-3}}{3 *    1.83 *10^{-3} }

=>         P =   1652 \  Pa

       

     

3 0
3 years ago
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