Answer:
Glaciologists use Glen–Nye Flow Law, to predict the movements of glaciers.
Explanation:
In some parts of the world, glaciers are an important natural resource. This is so because the nature and behaviour of glaciers are an impact the hydrologic, geologic, and ecological systems of their immediate location.
Due to the above, Glaciologists monitor and try to predict the movement and morphology of glaciers.
One of the techniques used by Glaciologists in the monitoring and prediction of glaciers in the use of markers.
The movement of markers is measured relative to the edges of the valley down which the glacier flows. The movement of the markers are then predicted using the Glen–Nye Flow Law.
The Glen–Nye Flow Law is expressed mathematically as follows:
∑= 
∑= shear strain (flow) rate
<em>r </em>= stress
<em>n</em> = a constant between 2–4 (typically 3 for most glaciers) that increases with lower temperature
<em>k </em> = a constant dependent on temperature
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Answer:
a) 2Hz
b) 0.5seconds
c) 0.34m/s
Explanation:
a) Frequency is defined as the number of oscillations completed by a wave in one second.
If my finger is dipped into a pan of water twice each second, it means that my hand has made 2 oscillations through the water in one second. An oscillation is a to and fro movement of a particle, body or wave through a medium.
Based on the conclusion, the frequency of the waterwaves will be 2Hertz or 2cycles/sec.
2) Period T of a wave is defined as the time taken by a wave to complete one oscillation. It is the reciprocal of the frequency of a wave.
T = 1/F
Given frequency = 2Hertz
T = 1/2
T = 0.5seconds
Period of the water wave is 0.5seconds
c) speed of the wave v is expressed according to the relationship:
velocity = frequency × wavelength
Given:
Frequency = 2Hertz
Wavelength = 0.17m (Since it is the difference between two successive crest or trough of a wave)
Velocity = 2×0.17
Velocity = 0.34m/s
W = 1/2k*x^2.
k = spring constant = 2500 n/m.
x = distance = 4 cm = 0.04m (convert to same units).
W = 1/2(2500)(0.04)^2 = 2J.
Answer:
This same Hawaii telescope, which would be 4 km across water level, can't provide an appropriate version of distanced planetary bodies. A further overview is provided below.
Explanation:
- The surface area of that same earth's orbit seems to be approximately 480 km heavy. The atmosphere isn't translucent to the only certain wavelength range of the radioactivity. Not because all-stars, as well as gliders, emit specific wavelengths, but several of them generate ultraviolet as well as infrared.
- Those same radiations have either been mediated primarily as well as passes through the atmosphere. Due to the Blockage, they can't even be interpreted with such a similar quality unless the telescope would be positioned throughout the portion of the atmosphere.
Since they move down their concentration gradient through a transport protein, they can release energy as a result of chemiosmosis. One example is GLUT1 which moves glucose down its concentration gradient into the cell.
