If the field strength between the plates is 9 volts per cm, then over a path of 1/2cm parallel to the field, the potential changes by (1/2) x (9 volts) = 4.5 volts.
Fnet = Fg sin 30 - Ff
ma = mg sin 30 - mew Fg cos 30
ma = mg sin 30 - mew mg cos 30
a = g sin 30 - mew gcos30
a - g sin 30 = - mew g cos 30
mew = -(a - g sin30)/(g cos 30)
mew = -(3m/s2 - 9.81sin30)/(9.81 cos 30)
mew = 0.22
The rubber protects him from being electrocuted by the flow of current going through the plug.
Hope this helped!!
Answer:
r1 -r2 = 3.75cm
Explanation:
Check the attached file for the solution
Answer:
Explanation:
We would most likely write the velocity of the ball as follow :
V(b<em>all</em> with respect to t<em>rain)</em> = Vbt
