Is there options for this??
Answer:
a) > x<-c(1,2,3,4,5)
> y<-c(1.9,3.5,3.7,5.1,6)
> linearmodel<-lm(y~x)
And the output is given by:
> linearmodel
Call:
lm(formula = y ~ x)
Coefficients:
(Intercept) x
1.10 0.98
b) 
And if we compare this with the general model 
We see that the slope is m= 0.98 and the intercept b = 1.10
Explanation:
Part a
For this case we have the following data:
x: 1,2,3,4,5
y: 1.9,3.5,3.7,5.1, 6
For this case we can use the following R code:
> x<-c(1,2,3,4,5)
> y<-c(1.9,3.5,3.7,5.1,6)
> linearmodel<-lm(y~x)
And the output is given by:
> linearmodel
Call:
lm(formula = y ~ x)
Coefficients:
(Intercept) x
1.10 0.98
Part b
For this case we have the following trend equation given:
And if we compare this with the general model
We see that the slope is m= 0.98 and the intercept b = 1.10
This is called the Phi Phenomenon.
This is an illusion of movement created when two or more adjacent lights blink on and off in quick succession; when two adjacent stationary lights blink on and off in quick succession; we perceive a single light moving back and forth between them. It is an optical illusion of perceiving a series of still images, when viewed in rapid succession, as continuous motion.
Explanation:
Given parameters:
Mass of Neil Armstrong = 160kg
Gravitational pull of earth = 10N/kg
Moon's pull = 17% of the earth's pull
Unknown:
Difference between Armstrong's weight on moon and on earth.
Solution:
To find the weight,
Weight = mass x acceleration due to gravity = mg
Moon's gravitational pull = 17% of the earth's pull = 17% x 10 = 1.7N/kg
Weight on moon = 160 x 1.7 = 272N
Weight on earth = 160 x 10 = 1600N
The difference in weight = 1600 - 272 = 1328N
The weight of Armstrong on earth is 1328N more than on the moon.
Learn more:
Weight and mass brainly.com/question/5956881
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