Treating the system as a point-like particle allows us to assign a quantity to the object and monitor this quantity throughout any changes. The complexity of the system which includes geometry, appearance, and extensions can complicate the studying of the system.
To find the solution to the problem, we would be using Planck's equation which is E = hv
Where:
E = energy
h = Planck's constant = 6.626 x 10-34 J·s
ν = frequency
Then, you’ll need a second equation which is c = λν
Where:
c = speed of light = 3 x 108 m/sec
λ = wavelength
ν = frequency
Reorder the equation to solve for frequency:ν = c/λ
Next, substitute frequency in the first equation with c/λ to get a formula you can use:
E = hν
E = hc/λ
But we are looking for the wavelength, so rearrange it more, then our final equation would be:
λ = hc / E
λ = (6.625E-34)(3.0E8 m/s) / (1.06E-13)
λ = 1.875E-12 m
Answer:
Speed in kilometer/hour = 6 kilometer / hour
Explanation:
Given;
Time taken to cover distance = 15 minute = 15 /60 = 0.25 hour
Distance of school = 1.5 kilometer
Find:
Speed in kilometer/hour
Computation:
Speed in kilometer/hour = Distance / Time
Speed in kilometer/hour = Distance of school / Time taken to cover distance
Speed in kilometer/hour = 1.5 / 0.25
Speed in kilometer/hour = 6 kilometer / hour
