That all adds up to $3.23 my friend
Since there is no repetition allowed, there are 10 possibilities for the 1st digit, 9 for the 2nd, 8 for the 3rd, and 7 for the 4th. This gives a total of (10)(9)(8)(7) = 5040 four-digit codes.
For all odd digits to be used, there are 5 possibilities for the 1st digit (1,3,5,7,9), 4 for the 2nd, 3 for the 3rd, 2 for the 4th. This gives a total of (5)(4)(3)(2) = 120 codes that only use odd digits.
Therefore there are 5040 - 120 = 4920 codes that do not consist of all odd digits. The probability is 4920/5040 = 41/42.
Answer: approximately 12.17 units
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Work Shown:
We'll use the tangent ratio to find r
tan(angle) = opposite/adjacent
tan(49) = 14/r
r*tan(49) = 14
r = 14/tan(49)
r = 12.1700143294271
r = 12.17
The radius is approximately 12.17 units long.
