
First 1: Store 3
Second 2: C.
Third: Marneisha
Four: 10
Five: Phone C.
Six: A.
Hopefully, this helps you!!

Alrighty
find where they intersect
9x²ln(x)=36ln(x)
divide both sides by 9
x²ln(x)=4ln(x)

so

so x=1 and and 2 (x can't be 0 or -2 because ln(0) and ln(-2) don't exist)
so intersect at x=1 and x=2
which is on top?
9(1.5)²ln(1.5)=20.25ln(1.5)
36ln(1.5)=36ln(1.5)
36ln(1.5) is on top
so
that will be
the area is

![[36x(ln(x)-1)-x^3(3ln(x)-1)]^2_1=](https://tex.z-dn.net/?f=%20%5B36x%28ln%28x%29-1%29-x%5E3%283ln%28x%29-1%29%5D%5E2_1%3D)

the area between the curves is 48ln(2)-29
Answer:
see explanation
Step-by-step explanation:
The n th term of a geometric progression is
•
= a₁ 
where a₁ is the first term and r the common ratio
given a₄ = 24, then
a₁
= 24 → (1)
Given a₈ =
, then
a₁
=
→ (2)
Divide (2) by (1)
=
= 
Hence r =
= 
Substitute this value into (1)
a₁ × (
)³ = 24
a₁ ×
= 24, hence
a₁ = 24 × 27 = 648
Answer: 31
Step-by-step explanation:
179 - 148 = 31