For this case we have to:
Given the quadratic equation of the form:

The roots are given by:

If we have: 
We can rewrite it in the following way:

Where:

Where we have:



By definition: 




Thus, the roots are given by imaginary numbers:

Answer:

<u>Answer:</u>
Standard form of a line passing through (-2, 4) and having slope of -1/7 is x + 7y = 26
<u>Solution:</u>
Given that we need to determine standard form of a line that goes through (-2 , 4) and slope of the line is -1/7
Standard form of line passing through point ( a , b ) and having slope m is given by
(y – b) = m ( x – a) --------(1)
In our case given point is ( -2 , 4 ) and slope is -1/7 that means
a = -2 , b = 4 , m = -(1/7)
On substituting given value of a , b and m is equation (1) we get


=> 7( y - 4 ) = -x – 2
=> 7y + x = -2 + 28
=> x + 7y = 26
Hence standard form of a line passing through (-2,4) and having slope of –(1/7) is x + 7y = 26
Rotate the shape about its central axis by making it stationary.
Answer:
just want
Step-by-step explanation:
the points are great
Answer:
The numbers are 4 and 1
Step-by-step explanation:
Let x and y be the numbers
Quotient is division
x/y = 4
x-y =3
Taking the first equation and multiplying each side by y
x = 4y
Replacing into the second equation
4y -y = 3
3y = 3
Divide by 3
3y/3 = 3/3
y=1
Now we can find x
x -y =3
x-1 =3
Add 1 to each side
x= 4