Answer:
Step-by-step explanation:
Hello!
X: Cholesterol level of a woman aged 30-39. (mg/dl)
This variable has an approximately normal distribution with mean μ= 190.14 mg/dl
1. You need to find the corresponding Z-value that corresponds to the top 9.3% of the distribution, i.e. is the value of the standard normal distribution that has above it 0.093 of the distribution and below it is 0.907, symbolically:
P(Z≥z₀)= 0.093
-*or*-
P(Z≤z₀)= 0.907
Since the Z-table shows accumulative probabilities P(Z<Z₁₋α) I'll work with the second expression:
P(Z≤z₀)= 0.907
Now all you have to do is look for the given probability in the body of the table and reach the margins to obtain the corresponding Z value. The first column gives you the integer and first decimal value and the first row gives you the second decimal value:
z₀= 1.323
2.
Using the Z value from 1., the mean Cholesterol level (μ= 190.14 mg/dl) and the Medical guideline that indicates that 9.3% of the women have levels above 240 mg/dl you can clear the standard deviation of the distribution from the Z-formula:
Z= (X- μ)/δ ~N(0;1)
Z= (X- μ)/δ
Z*δ= X- μ
δ=(X- μ)/Z
δ=(240-190.14)/1.323
δ= 37.687 ≅ 37.7 mg/dl
I hope it helps!
I'll assume you're asking for the initial price
Let's use x to represent it
The initial price plus 40 percent of that is $294
Let's write that out mathematically
x + (40/100)x = 294
x + 0.4x = 294
1.4x = 294
x = 210
The initial price is $210
Almons:walnuts:rasins=1:2:3
x=pounds of walnuts
y=pounds of almonds
z=pounds or rasins
2x=y
3x=z
subsitute
12x+9y+5z=15
12x+9(2x)+5(3x)=15
12x+18x+15x=15
45x=15
divide by 45
x=1/3
so
1/3 pound of walnuts
2x=y
2(1/3)=y=2/3
2/3 pounds of almonds
3x=z
3(1/3)=z
1=z
1 pound of rasins
1/3 pound walnuts
2/3 pound almonds
1 pound rasins
Answer:
l=15
Step-by-step explanation:
let length=l
width=w
l=3w-2
w=(l+2)/3
Perimeter P=2(l+w)=2[l+(l+2)/3]=2(4l+2)/3≤43
2(4l+2)≤129
8l+4≤129
8l≤125
l≤125/8
so l=15
________________
P=2(l+w)=2(3w-2+w)=8w-4≤43
8w≤47
w≤47/8
l≤141/8-2
l≤125/8
l=15
