Question

How many moles of gas occupy 98 l at a pressure of 2.8 atmospheres and a temperature of 292 k?

Answer 1

From the ideal gas equation, we know that PV = nRT
where, P = pressure, V = volume occupied, n = number of moles of gas, R = universal gas constant=0.082L atm mol-1 K-1 and T = temperature.
Given: P = 2.8 atm, V = 98 l and T = 292 k.
Therefore n =$\frac{PV}{RT}$ = $\frac{2.8 X 98}{0.082 X 292}$ = 11.46