<h3>
Answer:</h3>
8.01 mol MgO
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
- Analyzing Reactions RxN
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[RxN - Unbalanced] Mg + O₂ → MgO
[RxN - Balanced] 2Mg + O₂ → 2MgO
[Given] 8.01 moles Mg
[Solve] moles MgO
<u>Step 2: Identify Conversions</u>
[RxN] 2 mol Mg → 2 mol MgO
<u>Step 3: Stoich</u>
- [DA] Set up:

- [DA] Multiply/Divide [Cancel out units]:

The answer would be "Gas".
Answer:
0.266 moles of Na⁺
Explanation:
First step we dissociate the salt:
Na₃AsO₄ → 3Na⁺ + AsO₄⁻³
From 1 mol of sodium arsenate, we must have 3 moles of sodium cation and 1 mol of arsenate.
We determine the moles of salt:
18.4 g . 1 mol/ 207.89 g = 0.0885 moles of salt.
We apply the followring rule of three:
1 mol of salt has 3 moles of Na⁺
0.0885 moles of salt may have (0.0885 . 3) / 1 = 0.266 moles of Na⁺
Answer:
I believe your answer is B) make a prediction
Explanation:
Answer:
0
Explanation:
pure elements will always possess an oxidation number of 0, regardless of their charge.