The flavoring is what seems to appeal to underage users and it’s what makes vaping seem harmless
The mass of I₂ that contains 2.57×10²⁵ molecules is 10843.52 g
From a detailed understanding of Avogadro's hypothesis, we understood 1 mole of any substance contains 6.02×10²³ molecules. This implies that 1 mole of I₂ also 6.02×10²³ molecules i.e
<h3>6.02×10²³ molecules = 1 mole of I₂</h3>
Recall:
1 mole of I₂ = 2 × 127 = 254 g
Thus,
<h3>6.02×10²³ molecules = 254 g of I₂</h3>
With the above information, we can obtain the mass of I₂ that contains 2.57×10²⁵ molecules. This is illustrated below:
6.02×10²³ molecules = 254 g of I₂
Therefore,
2.57×10²⁵ molecules = 
<h3>2.57×10²⁵ molecules = 10843.52 g of I₂</h3>
Thus, the mass of I₂ that contains 2.57×10²⁵ molecules is 10843.52 g
Learn more: brainly.com/question/24848191
Answer:
First, it is easiest if you write the compete molecular equation:
AgNO3(aq) + KCl(aq) ==> AgCl(s) + KNO3(aq) .. molecular equation.
You must also know or look up which compounds are soluble (aq) and which are not (s). In this case, silver chloride (AgCl) is not soluble. Thus, the net ionic equation is...
Ag+(aq) + Cl-(aq) ==> AgCl(s)
Answer:
97.9 g/mol
Explanation:
<em>There is some info missing. I think this is the original question.</em>
<em>An analytical chemist weighs out 0.188 g of an unknown triprotic acid into a 250 mL volumetric flask and dilutes to the mark with distilled water. He then titrates this solution with 0.0600 M NaOH solutions. When the titration reaches the equivalence point, the chemist finds he has added 95.9 mL of NaOH solution.
</em>
<em>
Calculate the molar mass of the unknown acid.</em>
Let's consider the neutralization between a generic triprotic acid and NaOH.
H₃X + 3 NaOH → Na₃X + 3 H₂O
The moles of NaOH that reacted are:
0.0600 mol/L × 0.0959 L = 0.00575 mol
The molar ratio of NaOH to H₃X is 3:1. The moles of H₃X are 1/3 × 0.00575 mol = 0.00192 mol.
The molar mass of the acid is:
0.188 g / 0.00192 mol = 97.9 g/mol
Answer:
3) Rubidium reacts with rubidium nitrate to produce rubidium oxide and nitrogen gas
a- Write the chemical reaction
10Rb + 2RbNO3 → 6Rb2O + N2
