Answer:
0.035
Explanation:
<u>cv+ is the wild-type dominant allele over cv, therefore:</u>
- cv+cv+ and cv+cv cause wild-type phenotype for crossveinless
- cv cv causes the crossveinless phenotype
<u>Sb is a dominant mutant allele over wild-type Sb+, therefore:</u>
- Sb Sb and Sb Sb+ cause Stubble phenotype
- Sb+ Sb+ causes wild type phenotype for Stubble
<h3><u>Test cross</u></h3>
It's the cross between the heterozygous female with a homozygous recessive male. Remember that cv and Sb+ are the recessive alleles.
X 
-The male produces only 1 type of gamete: cv Sb+
-The female produces 4 types of gametes:
- cv Sb+ ] Parental
- cv+ Sb ] Parental
- cv Sb ] Recombinant
- cv+ Sb+ ] Recombinant
The genes are linked and separated by 7 map units. A distance of 7 mu means that 7% of the resulting gametes will be recombinant. Because there are 2 possible recombinant gametes, each of them will appear in 3.5% of the cases.
The genotypes and proportions of the offspring resulting from the test cross can be seen in the Punnett Square. The phenotypically wild-type individuals will have the genotype cv+ Sb+ / cv Sb+ (heterozygous for crossveinless and homozygous recessive for Stubble) and a 0.035 proportion.
Explanation:
please don't post such irrelevant questions
<span>test on homozygous recessive plant
</span><span>Similar to the homozygous alleles in every organisms, in the human body is composed of genes, and these usually come in pairs that are slightly different from each other. The different versions of genes are called alleles. Alleles are responsible for determining physical or notable characteristics and traits a specific person has. </span><span>
</span>
Dry season because it increases evaporation of water would increase the concentration of salt in the water