A child rides her bike at a rate of 12.0 km/hr down the street. A squirrel suddenly runs in front of her so she applies the brak
es and slows to 8.0 km/hr in 0.25 sec. What is the acceleration of the bike rider during this period?
2 answers:
it should be 16 kilometers per second
By v = u - at
<span>=>8 = 12 - a x 0.25 </span>
<span>=>a = 4/0.25 km/hr/sec </span>
<span>=>a = 16km/hr/sec
I hope this helped!</span>
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