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Travka [436]
3 years ago
6

A child rides her bike at a rate of 12.0 km/hr down the street. A squirrel suddenly runs in front of her so she applies the brak

es and slows to 8.0 km/hr in 0.25 sec. What is the acceleration of the bike rider during this period?
Physics
2 answers:
olya-2409 [2.1K]3 years ago
6 0

it should be 16 kilometers per second

Sedbober [7]3 years ago
3 0
By v = u - at 
<span>=>8 = 12 - a x 0.25 </span>
<span>=>a = 4/0.25 km/hr/sec </span>
<span>=>a = 16km/hr/sec

I hope this helped!</span>
You might be interested in
A copper cylinder is initially at 21.1 ∘C . At what temperature will its volume be 0.163 % larger than it is at 21.1 ∘C?
fomenos

To solve this problem we will apply the concepts related to the final volume of a body after undergoing a thermal expansion. To determine the temperature, we will use the given relationship as well as the theoretical value of the volumetric coefficient of thermal expansion of copper. This is, for example to the initial volume defined as V_1, the relation with the final volume as

V_2 = V_1 +0.163\% V_1

V_2 = V_1 +0.00163V_1

V_2 = 1.00163V_1

Initial temperature = 21.1\°C

Let T be the temperature after expanding by the formula of volume expansion

we have,

V_2 = V_1 (1+\gamma \Delta t)

Where \gamma is the volume coefficient of copper 5.1*10^{-5}/C

1.00163V_1 = V_1(1+\gamma(T-21.1\°))

1.00163 = 1+5.1*10^{-5}(T-21.1\°)

0.00163 = 0.000051T-0.0010761

T = 53.0608\°C

Therefore the temperature is 53.06°C

7 0
3 years ago
Could we see a galaxy that is 20 billion light-years away?.
vichka [17]

Answer:

No

Explanation:

20 billion light-years away are beyond our sight and perspective on Earth and wouldn't be observable in our universe.

7 0
2 years ago
A small sandbag is dropped from rest from a hovering hot-air balloon. (assume the positive direction is upward.) (a) after 1.5 s
marishachu [46]

solution:

We know v0 = 0, a = 9.8, t = 4.0. We need to solve for v

so,

we use the equation:

v = v0 + at

v = 0 + 9.8*4.0

v = 39.2 m/s

Now we just need to solve for d, so we use the equation:

d = v0t + 1/2*a*t^2

d = 0*4.0 + 1/2*9.8*4.0^2

d = 78.4 m

3 0
3 years ago
A train travels 160 km in 2 h. What is the train’s average speed in km/h?
loris [4]
The train’s average speed is 80km/h
3 0
3 years ago
Read 2 more answers
Add the vectors:
Anettt [7]

Vector 1 has components

x_1=(10\,\mathrm m)\cos20^\circ\approx9.40\,\mathrm m

y_1=(10\,\mathrm m)\sin20^\circ\approx3.42\,\mathrm m

and vector 2 has

x_2=(10\,\mathrm m)\cos80^\circ\approx1.74\,\mathrm m

y_2=(10\,\mathrm m)\sin80^\circ\approx9.85\,\mathrm m

Add these vectors to get the resultant, which has components

x_{\rm total}\approx11.133\,\mathrm m

y_{\rm total}\approx13.268\,\mathrm m

The magnitude of the resultant is

\sqrt{{x_{\rm total}}^2+{y_{\rm total}}^2}\approx17.321\,\mathrm m

with direction \theta such that

\tan\theta=\dfrac{y_{\rm total}}{x_{\rm total}}\implies\theta\approx50^\circ

or about 50º N of E.

8 0
3 years ago
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