P = 43 * 10^3
V = 12 L
P' =?
V' = 8 L
PV = P'V'
43*10^3* 12 = P' * 8
I know you can do it from here, mate ;)
Answer:
In the table, 1=46.7 °C, 1=165 J, 2=819 J, 3=1510 J, and 4=2830 J.
Other experiments determine that the material has a temperature of fusion of
fusion =235 °C and a temperature of vaporization of vapor=481 °C.
If the sample of material has a mass of =8.60 g, calculate the specific heat when this material is a solid, and when it is liquid, l
Quasar is famous for being an intergalactic object which is billions of years away from the earth yet can still be seen, unlike the other star body, unlike giant galaxies.
Hence, the fact that quasars can be detected from distances where even the biggest and most luminous galaxies cannot be seen means that "they must be intrinsically far more luminous than the brightest galaxies."
This condition, including other related evidence gotten in recent years concerning our galaxy, has shown that quasars are probably the central nuclei of very distant, very active galaxies.
The surprising thing was that quasars and active galaxies have a lot of mass in the center of the very small volume of the space.
Therefore, the surprising thing about quasars was that due to this mass and energy they are 100 times more luminous than Milky Way which means they have high recession velocity and a very large amount of red-shifting.
To learn more about quasars, refer: brainly.com/question/9965257
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E, 63% of the value. I forget the rationale behind it but I learnt that in engineering. 90% confident for that answer.
The distance covered by an object accelerating from rest is
D = (1/2) · (acceleration) · (time)² .
In this particular case, 'acceleration' is 9.8 m/s² ... due to gravity.
D = (1/2) · (9.8 m/s²) · (1.67 s)²
D = (4.9 m/s²) · (2.789 s²)
D = 13.67 meters
