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3 years ago

Highest to lowest -0.6 , 0.38, -0.41, 0.09, 0.7

Mathematics

1 answer:

34kurt3 years ago

3 0

Answer:0.38 0.09 0.7 -0.6 -0.41

Step-by-step explanation:

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Select the correct location on the image.

Ann [662]

Answer:

Step 3

Step-by-step explanation:

He added -6 and 8 when he should've multiplied following pemdas

( multiplied the 8 and 7 )

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3 years ago

What is the volume of the figure?

kaheart [24]

Answer:

The answer is C

Step-by-step explanation:

the volume equation is b*h*

the b= 2*8

the h= 3.

6 is the diagonal length of the side face which would be incorrect.

The answer would be 48. or C in the pic

3 0

3 years ago

Multiple choice please answer help

krok68 [10]

From the congruent alternate interior angles resulting from the parallel lines, we have the equation $8x-34=5x+2.$ Solving, we have $x=12^\circ$ and $\angle D E F =5x+2=\boxed{62^\circ}.$

6 0

3 years ago

Plz help asap with explanation and will get the brilliant

Elina [12.6K]

3x + y = -3
-2x + y = 7
Use elimination method
Subtract both equations
5x = -10, x = -2
Plug in -2 for x (any equation)
3(-2) + y = -3
-6 + y = -3
y = 3

Solution: x = -2, y = 3
Or as a coordinate: (-2, 3)

8 0

2 years ago

Read 2 more answers

segment BC is an are of a circle with radius 30.0 cm, and point P is at the center of curvature of the arc Segment DA is an arc

Elan Coil [88]

Answer:

The magnetic field is $B = 3.87 *10^{-6} \ T$

Direction is inward

Step-by-step explanation:

The diagram for this question is shown on the first uploaded image

From the question we are told that

The radius of BC is $r_{BC} = 30 \ cm = 0.30 \ m$

The radius of DA is $r _{DA} = 20 \ cm = 0.20 \ m$

The length of CD is $r_{CD} = 10 cm = 0.1 \ m$

The length of AB is $r_{AB} = 10 cm = 0.1 \ m$

The current is $I = 11.4A$

The magnetic field is mathematically represented as

$B = B_{BC} + B_{DA} + B_{CD} + B_{AB}$

$B = \frac{\mu_o I}{4 \pi } [ \frac{\theta_{DA}}{r_{DA}} + \frac{\theta_{BC}}{r_{BC}}+ \frac{\theta_{CD}}{r_{CD}}+\frac{\theta_{AB}}{r_{AB}}]$

Where

$\theta_{BC} = \theta_{DA} = \frac{2\pi}{3}$

Where $\frac{2 \pi}{3} = 120^o$

$\theta_{CD} = \theta_{AB} = 0^o$

$B = \frac{\mu_o I}{4 \pi } [ \frac{\frac{2\pi}{3} }{0.20} - \frac{\frac{2\pi}{3}}{0.30}}+ \frac{0}{0.10}+\frac{0}{0.10}]$

$B = 3.87 *10^{-6} \ T$

The direction is into the page

This because the magnitude of the magnetic field due to arc BC whose direction is outward is less than that of DA whose direction is inward

This is because according to Fleming's Left Hand Rule the direction of current is perpendicular to the direction of magnetic field so since current in arc BC and DA are moving in opposite direction their magnetic field will also be moving in opposite direction

3 0

3 years ago