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choli [55]
4 years ago
14

Highest to lowest -0.6 , 0.38, -0.41, 0.09, 0.7

Mathematics
1 answer:
34kurt4 years ago
3 0

Answer:0.38 0.09 0.7 -0.6 -0.41

Step-by-step explanation:

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Factor the following using GCF and show work. 6x^2+42x-18
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The greatest common factor is 6. Thus means we divide every part of the expression by 6.

6x^2/6 = x^2
42x/6 = 7x
-18/6 = -3

Your new expression is 6(x^2 + 7x -3).
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Best known for its testing program, ACT, Inc., also compiles data on a variety of issues in education. In 2004 the company repor
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Answer:

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

p \sim N(p, \sqrt{\frac{p(1-p)}{n}})

So then:

\mu_p = 0.74

\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

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3 years ago
Ava is saving for a new computer that coat 1,218 she already has half saved of the money. Ava earns $14.00 per hour. How many ho
ollegr [7]

Answer:

43.5

Step-by-step explanation:

First

1218 divided by 2

= 609

Second

609 divided by 14 is =43.5

43.5 is the answer

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Answer:

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Step-by-step explanation:

find the attachment of the attachment good morning baby girl I wanted to know how many people will be

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