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enyata [817]
3 years ago
12

Can Someone explain the steps for this ?

Physics
2 answers:
telo118 [61]3 years ago
8 0
All you have to do is resolve the velocity into x and y components.
Now, since you have to determine the height of the window, only y component of velocity of the bag will affect its vertical motion.
Also, it just reaches the window which could only happen if its vertical component of final velocity becomes zero.
All you have to do is, use kinematic equation,

v^2 - u^2 = 2gh

v= final velocity(vertical component) = 0 m/s
u = initial velocity (vertical component)
g = acceleration due to gravity
h = height of the window from the ground

Plug all the given values to find h
NARA [144]3 years ago
3 0

Answer:

h = 10.0 m

Explanation:

As we know that the initial velocity of the bag is 16.2 m/s at an angle of 60 degree

so here we have

v_x = 16.2 cos60

v_x = 8.1 m/s

v_y = 16.2 sin60

v_y = 14.03 m/s

now we know that the bag just reaches the window so here at the point when bag reaches to the window its vertical speed must be zero

so we have

v_f^2 - v_i^2 = 2 a d

0 - (14.03)^2 = 2(-9.81)(h)

h = 10.0 m

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Determine the image distance and image height for a 5.00 cm tall object placed 30.0 cm from a double convex lens with a focal le
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Answer:

The image distance is 30 cm

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Explanation:

The formula for calculating the image distance is expressed as

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By substituting these values into the formula,

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Taking the reciprocal of both sides,

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magnification = image height/object height = - v/u

Given that object height = 5 cm, then

image height/5 = - 30/30 = - 1

image height = - 5 * 1

image height = - 5 cm

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