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poizon [28]
3 years ago
9

Hooke's Law Practice

Physics
1 answer:
Oxana [17]3 years ago
8 0

Answer:sheeExplanation:

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Two objects form a closed system. One object, which is at 400 K, absorbs 25.0 kJ of heat from the other object,which is at 500 K
Damm [24]

Explanation:

The given data is as follows.

       T_{1} = 400 K,     T_{2} = 500 K,  

\Delta Q = 25 kJ = 25000 J   (as 1 kJ = 1000 J)

Now, we will calculate the change in entropy as follows.

            \Delta S = \frac{\Delta Q}{\Delta T}

Putting the given values into the above formula as follows.

           \Delta S = \frac{\Delta Q}{\Delta T}

                      = \frac{25000 J}{(500 K - 400 K)}      

                      = 250 J/K

Hence, we can conclude that change in entropy is 250 J/K.

4 0
3 years ago
A passenger is running inside a stationary train with some speed and looks at the person standing on the platform. Describe the
Lubov Fominskaja [6]

Answer:

Doppler effect

Explanation:

this means that at one point when the person running is close to the observer it will appear to run fast but slower as he moves away from the observer

4 0
2 years ago
The path of electric current is known as___
777dan777 [17]

here the answer to your question hope it helps you

electric circuit

7 0
3 years ago
Read 2 more answers
How do you balance this equation Mg+ O2= MgO
Anuta_ua [19.1K]

Answer:

2 Mg(s) + O2(g) → 2 MgO(s)

As magnesium (Mg) has a valency of +2, and oxygen (O) has a valency of -2, the ratio would be 1:1, and magnesium oxide would be represented as MgO. It is insoluble in water, hence it has the subscript as a solid, represented by (s). In order to use up the diatomic oxygen (O2), there needs to be two moles of magnesium (2Mg) on the reactant side. This would produce 2 moles of MgO on the product side.

Explanation:

8 0
4 years ago
Germanium to which 1024 m-3 Ga atoms have been added is an extrinsic semiconductor at room temperature, and virtually all the Ga
Svetlanka [38]

Answer:

Electrical Conductivity is 3200 (\Omega m)^{-1}

Solution:

As per the question:

N_{A} = 10^{24}\ m^{- 3}\ Ga\ atoms

Mobility of electrons, \mu_{e} = 0.26\ m^{2}/ Vs

Mobility of holes, \mu_{h} = 0.020\ m^{2}/ Vs

Charge, Q = 1.6\times 10^{- 19}\ C

Now,

The formula for the conductivity is given by:

\sigma = N_{A}Q\mu_{h}

\sigma = 10^{24}\times 1.6\times 10^{- 19}\times 0.020} = 3200(\Omega m)^{-1}

5 0
3 years ago
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