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3 years ago

Help me I have no idea how to do 18

Mathematics

1 answer:

sleet_krkn [62]3 years ago

5 0

First, subtract px2 from both sides.

Now you have:

x3 - px2 = (1 - p) x1

Next, divide both sides by (1 - p)

So now you have

x3 - px2/(1 - p) = x1

...as your final answer

*You can decide if you want to leave the parenthesis in your final answer, I left them there so it could be visible where I put them. :)

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Answer:

I think its x=2 sorry if im wrong

Step-by-step explanation:

6 0

3 years ago

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Type the correct answer in each box. A circle is centered at the point (5, -4) and passes through the point (-3, 2). The equatio

Galina-37 [17]

Answer:

$(x+ \boxed{-5})^2+(y+\boxed4)^2=\boxed{100}$

Step-by-step explanation:

Given:

Center of circle is at (5, -4).

A point on the circle is $(x_1,y_1)=(-3, 2)$

Equation of a circle with center $(h,k)$ and radius 'r' is given as:

$(x-h)^2+(y-k)^2=r^2$

Here, $(h,k)=(5,-4)$

Radius of a circle is equal to the distance of point on the circle from the center of the circle and is given using the distance formula for square of the distance as:

$r^2=(h-x_1)^2+(k-y_1)^2$

Using distance formula for the points (5, -4) and (-3, 2), we get

$r^2=(5-(-3))^2+(-4-2)^2\\r^2=(5+3)^2+(-6)^2\\r^2=8^2+6^2\\r^2=64+36=100$

Therefore, the equation of the circle is:

$(x-5)^2+(y-(-4))^2=100\\(x-5)^2+(y+4)^2=100$

Now, rewriting it in the form asked in the question, we get

$(x+ \boxed{-5})^2+(y+\boxed4)^2=\boxed{100}$

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3 years ago

PLS HELP WILL MARK YOU BRAINLIEST!! No fake answers pls

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Answer:

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2 years ago

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6x + 4y = -14 -X-5y=11

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Answer:

x= -1; y= -2

Step-by-step explanation:

A: 6x+4y= -14

B: -x-5y=11

6B is : -6x-30y=66

A+6B is : -26y=52

so y= -2

so A becomes : 6x+4.(-2)= -14

so x= -1

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Why is it important to use the order of operations to evaluate algebraic experssions?

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