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3 years ago

14

An ad for a laptop claims that the laptop weighs 10% less than its main competitor. If the competitor's laptop weighs 1.1 kilos,

how much does the laptop weigh?
A. 1.09 kilos
B. 0.9 kilos
C. 0.99 kilos
D. 1 kilo
E.1.01 kilos

2 answers:

Drupady [299]3 years ago

7 0

C My dude dude dude dude

lozanna [386]3 years ago

4 0

C because its C your welcome

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1. A plane is flying at an altitude of 13000 feet. The angle of depression from the plane to a control tower is 20 degrees. The

Mariulka [41]

Answer:

see explanation

Step-by-step explanation:

There is a right triangle formed between the height above the tower to the plane, the horizontal and the line from the tower to the plane.

The height above the tower to the plane = 13000 - 150 = 12850 ft

The angle between the plane and the tower is 20° , angle of depression.

Using the tangent ratio in the right triangle formed, with the adjacent side being the horizontal ( hor ) distance, then

tan20° = $\frac{opposite}{adjacent}$ = $\frac{12850}{hor}$ ( multiply both sides by hor)

hor × tan20° = 12850 ( divide both sides by tan20° )

hor = $\frac{12850}{tan20}$ ≈ 35305 ft ( to the nearest foot )

(2)

Arianna is 60 + 5 = 65 ft above the ground ( to her eye level )

Using the right triangle formed with legs 65 and 37 and angle of depression x, then

tanx° = $\frac{opposite}{adjacent}$ = $\frac{37}{65}$ , thus

x = $tan^{-1}$ ( $\frac{37}{65}$ ) ≈ 30° ( to the nearest degree )

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3 years ago

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A family has two cars. During one particular week, the first car consumed 15 gallons of gas. The two cars Drove a combined total

julia-pushkina [17]

Answer:

Car 1 : 40 miles per gallon

Car 2: 25 miles per gallon

Step-by-step explanation:

family has two cars. During one particular week, the first car consumed 15 gallons of gas. The second car consumed 25 gallons of gas. The two cars Drove a combined total of 1475 miles and the sum of their fuel efficiency was 65 miles per gallon. What were the fuel efficiency of each of the cars that week

Given that :

Fuel efficiency , car 1 = x

Fuel efficiency , car 2 = y

x + y = 65 - - (1)

15x + 35y = 1475 - - - (2)

x = 65 - y

15(65-y) + 35y

975 - 15y + 35y = 1475

20y = 14875 - 975

20y = 500

y = 25

Put y = 25 in (1)

x + y = 65

x + 25 = 65

x = 65 - 25

x = 40

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2 years ago

An electronic store sells a large flat screen television for $1,699. Last month, the store sold 8 of these television sets. Abou

serg [7]

1699 / 8 = 212.375 and then round $212.38 per TV

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3 years ago

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Which whole number is equivalent to 12/3 ?

11Alexandr11 [23.1K]

Answer:

4

Step-by-step explanation:

12 divided by 3 is 4. It's that simple!

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2 years ago

Eliminate the parameter and obtain the standard form of the rectangular equation. line through (x1, y1) and (x2, y2): x = x1 + t

Helen [10]

The parametric equations for the line passes through the points (X₁ , Y₁) and (X₂ , Y₂) are :

X = X₁ + t (X₂ - X₁) ......................... (1)

Y = Y₁ + t (Y₂ - Y₁) .......................... (2)

For eliminating the parameter (t) , first we will solve any one equation for 't' and then substitute that into another equation.

From the equation (1),

⇒ t = $\frac{X- X1}{(X2 - X1)}$

Substituting this t = $\frac{X- X1}{(X2 - X1)}$ into the equation (2), we will get :

Y = Y₁ + $\frac{(X- X1)}{(X2 - X1)}$ (Y₂ - Y₁)

Y = Y₁ + $\frac{(X- X1)(Y2 - Y1)}{(X2 - X1)}$

So, this is the standard form of rectangular equation.

For two given points (0, 0) and (4, -4)

X₁ = 0 , Y₁ = 0, X₂ = 4 and Y₂ = -4

For finding the parametric equations, we will plug these values into the given parametric equations.

X = X₁ + t (X₂ - X₁)

⇒ X = 0+ t (4 - 0)

⇒ X = 4t

and Y = Y₁ + t (Y₂ - Y₁)

⇒ Y = 0+ t (-4 - 0)

⇒ Y = - 4t

So, the parametric equations for the line passing through (0,0) and (4, -4) are: X = 4t and Y = -4t

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3 years ago