Answer:
14/5
Step-by-step explanation:
Answer:
Option A. √(x + 1)
Step-by-step explanation:
Data obtained from the question include:
f(x) = √(x² – 1)
g(x) = √(x – 1)
(f/g) (x) =..?
(x² – 1) => difference of two square
(x² – 1) => (x – 1)(x + 1)
f(x) = √(x² – 1)
f(x) = √(x – 1)(x + 1)
(f/g) (x) = f(x) /g(x)
f(x) = √(x – 1)(x + 1)
g(x) = √(x – 1)
(f/g) (x) = √(x – 1)(x + 1) / √(x – 1)
(f/g) (x) = √[(x – 1)(x + 1) / (x – 1)]
(f/g) (x) = √(x + 1)
Answer:
Null hypothesis is: U1 - U2 ≤ 0
Alternative hypothesis is U1 - U2 > 0
Step-by-step explanation:
The question involves a comparison of the two types of training given to the salespeople. The requirement is to set up the hypothesis that type A training leads to higher mean weakly sales compared to type B training.
Let U1 = mean sales by type A trainees
Let U2 = mean sales by type B trainees
Therefore, the null hypothesis (H0) is: U1 - U2 ≤ 0
This implies that type A training does not result in higher mean weekly sales than type B training.
The alternative hypothesis (H1) is: U1 - U2 > 0
This implies that type A training indeed results in higher mean weekly sales than type B training.
Answer:
(p - 8)(p - 9)
Step-by-step explanation:
We need 2 numbers whose product is + 72 and whose sum = -17.
They are -8 and -9
