Answer:
![y=-x+r](https://tex.z-dn.net/?f=y%3D-x%2Br)
Step-by-step explanation:
we know that
The tangency point on the x-axis is (r,0)
The tangency point on the y-axis is (0,r)
Find the slope of the line containing the points of tangency
![m=\frac{0-r}{r-0}=-1](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B0-r%7D%7Br-0%7D%3D-1)
Remember that the equation of the line into slope intercept form is equal to
![y=mx+b](https://tex.z-dn.net/?f=y%3Dmx%2Bb)
where
m is the slope
b is the y-coordinate of the y-intercept
In this problem we have
![m=-1](https://tex.z-dn.net/?f=m%3D-1)
![b=r](https://tex.z-dn.net/?f=b%3Dr)
substitute
![y=-x+r](https://tex.z-dn.net/?f=y%3D-x%2Br)
Answer:
The answer is 12.
Step-by-step explanation:
12 is the coefficient because it is the number multiplied by the variable p in the equation.
I hope this helps u! :D
16, 5, 28 from top to bottom
<span>6(2*144) + 6(2*12.5) + 3(144) = 2310</span>
If you know the perimeter of a rectangle but not its length or width can u calculate its area