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saveliy_v [14]
3 years ago
13

A bag contains 44 red balls and 55 blue balls. 22 balls are selected at random. find the probability of selecting 22 red balls.

Mathematics
1 answer:
scoundrel [369]3 years ago
5 0
<span># of ways to select 2 red balls: 5C2 = 10
# of random pairs of balls: 12C2 = 66</span>
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x P(x) 0 0.25 1 0.3 2 0.1 3 0.35 Find the standard deviation of this probability distribution. Give your answer to at least 2 de
barxatty [35]

Answer:

The standard deviation of this probability distribution is 1.2.

Step-by-step explanation:

We have that:

P(X = 0) = 0.25

P(X = 1) = 0.3

P(X = 2) = 0.1

P(X = 3) = 0.35

Mean:

Each value multiplied by its probability. So

M = 0*0.25 + 1*0.3 + 2*0.1 + 3*0.35 = 1.55

Variance:

Sum of the squares of the values subtracted from the mean, and multiplied by its probability.

V = 0.25*(0-1.55)^2 + 0.3*(1-1.55)^2 + 0.1*(2-1.55)^2 + 0.35*(3-1.55)^2 = 1.4475

Standard deviation:

Square root of the variance. So

S = \sqrt{V} = \sqrt{1.4475} = 1.2

The standard deviation of this probability distribution is 1.2.

6 0
3 years ago
What is the solution to the equation
Dafna11 [192]
\sqrt{4t+5}=3-\sqrt{t+5}\\\\D:4t+5\geq0\ \wedge\ t+5\geq0\ \wedge\ \sqrt{t+5}\leq3\\\\t\geq-\dfrac{5}{4}\ \wedge\ t\geq-5\ \wedge\ t\leq6

therefore
D:x\in\left< -\dfrac{5}{4};\ 6\right>

\sqrt{4t+5}=3-\sqrt{t+5}\ \ \ |^2\\\\(\sqrt{4t+5})^2=(3-\sqrt{t+5})^2\ \ \ |use:(a-b)^2=a^2-2ab+b^2\\\\4t+5=3^2-2\cdot3\cdot\sqrt{t+5}+(\sqrt{t+5})^2\\\\4t+5=9-6\sqrt{t+5}+t+5\ \ \ \ |-t\\\\3t+5=14-6\sqrt{t+5}\ \ \ \ |-14\\\\3t-9=-6\sqrt{t+5}\ \ \ \ |change\ signs
9-3t=6\sqrt{t+5}\ \ \ \ |:3\\\\3-t=2\sqrt{t+5}\ \ \ \ |^2\\\\(3-t)^2=(2\sqrt{t+5})^2\\\\3^2-2\cdot3\cdot t+t^2=4(t+5)\\\\9-6t+t^2=4t+20\ \ \ |-4t-20\\\\t^2-10t-11=0\\\\t^2+t-11t-11=0\\\\t(t+1)-11(t+1)=0\\\\(t+1)(t-11)=0\iff t+1=0\ \vee\ t-11=0\\\\t=-1\in D\ \vee\ t=11\notin D
Answer: t = -1.


7 0
3 years ago
Read 2 more answers
#7:Write the expression in simplest<br> radical form.<br> V24x5y2
vazorg [7]

2x^2y√6x


the image has the answer in a mor clear form


8 0
3 years ago
Using the table for many repetitions of the experiment of tossing a coin 10 times, what is the mean number of heads in 50 repeti
PtichkaEL [24]
When there are 1000 repetitions, the mean will be 5.002.

The charts that you have list the number of total heads when you flip the coin 10 times in each trial.

Multiply the total of each by the number number of heads for that category and divide by 1000.

1 x 0
8 x 1
43 x 2
117 x 3
2017 x 4
248 x 5
203 x 6
121 x 7
45 x 8
6 x 9
1 x 10

If you add up those products and divide by 1000, you have 5.002.

Using the law of large numbers, the experiment with 1000 rolls will be the closest to the theoretical amount.
7 0
3 years ago
Please help me, if you help then thanks!
vredina [299]

The formula for volume always involves three dimensions.  

In this case, the volume of a cube is V=s^3, where s is the side length of the cube.

To solve for that side length, you'd need to use a cube root.

8 0
3 years ago
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