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3 years ago

If p:q=2/3:3 and p:r=3/4:2/3 calculate the ratio p:q:r. Giving the answer in its simplest form

Mathematics

1 answer:

adelina 88 [10]3 years ago

6 0

Answer:

Given

if p:q=2/3:3 and p:r=3/4:1/2, calculate the ratio p:q:r giving your answer in its simplest form

We need to find the ratio p:q:r

Given p:q = 2/3 : 3 = 2/3 / 3 = 2/9

and p : r = 3/4 : 1/2 = 3/4 / 1/2 = 3/2

Now p/q = 2/9 and p/r = 3/2

We need to make p equal numerators so we get

p/q = 2/9 x 3/3 = 6/27 and

p/r = 2/3 x 3/2 = 6/4

Therefore p : q : r = 6 : 27 : 4

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Please help me, this is PEDMAS

rusak2 [61]

Answer:

1). 183

2). 83

3). 353

4). -2652

5). 59

6). 510

7). -293

8). 79

9). 78

10). 87

Step-by-step explanation:

Considering order of operation, parenthesis must be simplified first.

The solutions to the given questions are shown below;

$1). \ \ 5+(7\times (3+2)^2) + 3=8 + (7\times (5)^2) = 8 + (7\times 25) = 8 + 175 = 183$

$2). \ 16+(8+ (6+2)^2) - 5=16-5 + (8+ (8)^2) = 11 + (8+64) = 11 + 72 = 83$

$3). \ (15+ 3)^2 + ((14+6)+3^2)= (18)^2 + ((20) + 9) = 324 + (29) = 353$

$4). \ ((11+ 2)-(24+2)^2)\times 2^2 = (13 - 676) \times 4 = (-663)\times 4 = -2652$

$5). \ ((4+3)^2+ 6) -5+3^2= (49 + 6) - 5 + 9= (49+6+9) - 5 = 64-5 = 59$

$6). \ (20+ 2)^2 +((15+7)+2^2)= (484) + (22+ 4)= 484 + 26 =510$

$7). \ ((12 + 4)- (15+3)^2+ 5^2 = (16 - 324) + 25 = -318 + 25 = -293$

$8). \ (6^2+ (24+ 3+5^2)) - 3^2= (36 + (52)) - 9 = (88) - 9 = 79$

$9). \ ((10-4)^2\times 2) + 2 + 2^2= ((6)^2 \times 2) + 2 + 4 = (36\times 2)+ 6 = 72 + 6 = 78$

$10). \ (7^2 + (16 + 8 + 2^2)) + 3^2 = (49 + 28) + 9 = 78 + 9 = 87$

3 0

2 years ago

Factor the expression 20k + 50

Yuliya22 [10]

Answer is 10(2k+5)

-----------------------------------

Work Shown:

20k+50 = 10*2k + 10*5
20k+50 = 10(2k+5)

Note how we can distribute the 10 back in to check our work
10(2k+5) = 10(2k)+10(5) = 20k+50
so that confirms we have the right answer

Another thing to notice is that 10 is the largest factor that we can pull out of 20k and 50. The value 10 is the GCF (greatest common factor) of 20 and 50.

4 0

2 years ago

DA−2qA=B^3<br> Solve for A

a_sh-v [17]

Answer:

$a=\frac{b^{3} }{d-2q}$