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Ann [662]
3 years ago
12

Avogrados number of representatives particles is equal to one what?​

Chemistry
1 answer:
kotykmax [81]3 years ago
5 0

Answer:

Avogadro number of representatives particles is equal to one mole.

Explanation:

The number 6.022 × 10²³ is called Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

17 g of ammonia = 1 mole =  6.022 × 10²³ molecules of ammonia

12 g of carbon = 1 mole = 6.022 × 10²³ atoms of carbon

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

You might be interested in
How does distillation separate a solvent from a solute?
lord [1]

Answer:

Distillable mixtures may contain a solid in a liquid. This method takes advantage of the boiling point of the substances.

In this way, for the distillation to take place correctly, the mixture must be boiled until the boiling point of the solvent is reached, which will then become steam and can be led to a cooled container, in which it will condense and recover its liquidity.  On the other hand the solute will remain in the container without alterations; having in both cases pure substances, free of the initial mixture.

5 0
3 years ago
A chemist adds 215.0mL of a 6.0x10^−5/mmolL mercury(II) iodide HgI2 solution to a reaction flask. Calculate the micromoles of me
Snezhnost [94]

The micromoles of mercury(II) iodide : 0.013 μ moles

<h3>Further explanation</h3>

Given

215.0mL of a 6.0x10⁻⁵mmol/L HgI₂

Required

micromoles of HgI₂

Solution

Molarity(M) = moles of solute per liters of solution

Can be formulated :

M = n : V

n = moles

V = volume of solution

V = 215 mL = 0.215 L

so moles of solution :

n = M x V

n = 6.10 mmol/L x 0.215 L

n = 1.312 . 10⁻⁵ mmol

mmol = 10³ micromol

so 1.312 mmol = 1.312.10⁻⁵ x 10³ = 0.01312 micromoles ⇒ 2 sif fig = 0.013 μ moles

6 0
2 years ago
Is copper II chloride mixed with water an element, compound, or mixture? If it's a mixture is it homogeneous or heterogeneous?
Fittoniya [83]

Answer:

1. mixture

2. Homogenous

Explanation:

Copper II chloride is a compound because it consists of elements that are chemically combined together. When a solute in this case, copper II chloride is mixed with water- a solvent, the result is a homogenous mixture.

Homogenous substances are formed when a solute and a solvent combine, resulting in a mixture with uniform properties. Mixtures can be separated using relevant separation techniques.

7 0
2 years ago
Help please
Lana71 [14]

Answer:

Yes

Explanation:

Based on the graph, nuclear energy is one of the least contributors of CO2 emissions.

You would support this source of energy .

8 0
3 years ago
An electron in the n = 3 energy level of the hydrogen atom emits a photon with wavelength 656.27 nm. What is the change in energ
Lady_Fox [76]

Answer:change in energy of the electron=3.052x 10^-19J

which energy level does it move= level 2 , n=2

Explanation:

Using the formulae

1/λ = R (1/n1²- 1/n2²)

Where λ= 656.27 nm

1 nm = 1 x 10^-9 m

656.27 nm = 656.27 x 1 x 10^-9 =6.5726 x 10^-7

R =Rydberg constant = 1.0967 x 10^7m-1

1/λ = R (1/n1²- 1/n2²)

1/6.5726 x 10^-7=1.0967 x 10^7(1/n1²- 1/3²)

1/n1²=(1/6.5726 x 10^-7 x   1/1.0967 x 10^7) + 1/9

1/n1²=1,521,467.9 x 9.118x10^-8 + 0.1111

1/n1² =0.2498

n1²= 1/0.2498 =4

n1= \sqrt{4} = 2

it moves to energy level 2

b) Change in energy =ΔE = Rhc (1/n1²- 1/n2²)

Where R==Rydberg constant = 1.0967 x 10^7m-1

h = Planck constant = 6.626x 10^-34js

c = speed of light = 3.0 x 10^8 x m/s

ΔE = Rhc (1/n1²- 1/n2²)

=1.0967 x 10^7m-1 x6.626x 10^-34js X 3.0 x 10^8 x m/s (1/2² - 1/3²)

=2.18 x 10-18 x ( 1 /4 - 1/9)

=3.052x 10^-19J

7 0
3 years ago
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