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Ann [662]
3 years ago
12

Avogrados number of representatives particles is equal to one what?​

Chemistry
1 answer:
kotykmax [81]3 years ago
5 0

Answer:

Avogadro number of representatives particles is equal to one mole.

Explanation:

The number 6.022 × 10²³ is called Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

17 g of ammonia = 1 mole =  6.022 × 10²³ molecules of ammonia

12 g of carbon = 1 mole = 6.022 × 10²³ atoms of carbon

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

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3 0
3 years ago
Which of the following is not true about limiting and excess reagents?
Bogdan [553]

Answer : The incorrect option is, (d) The reactant that was the smallest given mass is the limiting reagent.

Explanation :

Limiting reagent : It is the reagent that is completely consumed in the chemical reaction when the chemical reaction is complete. No amount is left after the reaction is complete. The amount of product obtained is determined by the limiting reagent. A balanced equation is necessary to determine which reactant is limiting reagent.

Excess reagent : It is the reagent that are not completely consumed in the chemical reaction. That means the reagent is in excess amount. Some amount of the excess reagent is left over after the reaction is complete.

From this we conclude that the options, A, B and C are correct. While the option D is incorrect.

Option D is incorrect because it is not necessary the reactant that was the smallest given mass is the limiting reagent but it is judge by the number of moles present in the reaction.

Hence, the incorrect option is, (d)

4 0
3 years ago
Define all of the different changes of state and what the states they change to and form
Lubov Fominskaja [6]

Processes in which matter changes between liquid and solid states are freezing and melting. Processes in which matter changes between liquid and gaseous states are vaporization, evaporation, and condensation. Processes in which matter changes between solid and gaseous states are sublimation and deposition.

3 0
3 years ago
Read 2 more answers
an aqeous solution of oxalic acid h2c2o4 was prepared by dissolving a 0.5842g of solute in enough water to make a 100 ml solutio
vampirchik [111]

The question is incomplete, here is the complete question:

An aqeous solution of oxalic acid was prepared by dissolving a 0.5842 g of solute in enough water to make a 100 ml solution a 10 ml aliquot of this solution was then transferred to a volumetric flask and diluted to a final volume of 250 ml. How many grams of oxalic acid are in 100. mL of the final solution?

<u>Answer:</u> The mass of oxalic acid in final solution is 0.0234 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}     ......(1)

Given mass of oxalic acid = 0.5842 g

Molar mass of oxalic acid = 90 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

\text{Molarity of oxalic acid solution}=\frac{0.5842\times 1000}{90\times 100}\\\\\text{Molarity of oxalic acid solution}=0.0649M

To calculate the molarity of the diluted solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated oxalic acid solution

M_2\text{ and }V_2 are the molarity and volume of diluted oxalic acid solution

We are given:

M_1=0.0649M\\V_1=10mL\\M_2=?M\\V_2=250.0mL

Putting values in above equation, we get:

0.0649\times 10=M_2\times 250.0\\\\M_2=\frac{0.0649\times 10}{250}=0.0026M

Now, calculating the mass of glucose by using equation 1, we get:

Molarity of oxalic acid solution = 0.0026 M

Molar mass of oxalic acid = 90 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

0.0026=\frac{\text{Mass of oxalic acid solution}\times 1000}{90\times 100}\\\\\text{Mass of oxalic acid solution}=\frac{0.0026\times 90\times 100}{1000}=0.0234g

Hence, the mass of oxalic acid in final solution is 0.0234 grams

6 0
4 years ago
socratic For the following reaction, 25.6 grams of hydrochloric acid are allowed to react with 52.4 grams of barium hydroxide .
TEA [102]

Answer:

63.7g BaCl₂

Explanation:

Based on the chemical reaction:

2HCl + Ba(OH)₂ → BaCl₂ + 2H₂O

<em>2 moles of HCl reacts per mole of barium hydroxide</em>

<em>  </em>

To solve this question, we need to convert the moles of each reactant to moles and, using the chemical reaction, find limiting reactant as follows:

<em>Moles Ba(OH)₂ - Molar mass: 171.34g/mol-</em>

52.4g Ba(OH)₂ * (1mol / 171.34g) = 0.306 moles Ba(OH)₂

<em>Moles HCl - Molar mass: 36.46g/mol-</em>

25.6g HCl * (1mol / 36.46g) = 0.702 moles HCl

For a complete reaction of 0.702 moles HCl are required:

0.702 moles HCl * (1mol Ba(OH)₂ / 2mol HCl) = 0.351 moles of Ba(OH)₂

As there are just 0.306 moles, limiting reactant is Ba(OH)₂

That means the maximum amount of BaCl₂ produced is:

0.306 moles Ba(OH)₂ * (1mol BaCl₂ / 1 mol Ba(OH)₂) = 0.306 moles BaCl₂

In mass -Molar mass BaCl₂: 208.23g/mol-

0.306 moles BaCl₂ * (208.23g / mol) = 63.7g BaCl₂

3 0
3 years ago
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