Here is the full question:
Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/min, and the circulated air is then pumped out at the same rate. If there is an initial concentration of 0.2% carbon dioxide, determine the subsequent amount in the room at any time.
What is the concentration at 10 minutes? (Round your answer to three decimal places.
Answer:
0.046 %
Explanation:
The rate-in;
= 0.8
The rate-out
=
=
We can say that:
where;
A(0)= 0.2% × 6000
A(0)= 0.002 × 6000
A(0)= 12
Integration of the above linear equation =
so we have:
∴
Since A(0) = 12
Then;
Hence;
∴ the concentration at 10 minutes is ;
= %
= 0.0456667 %
= 0.046% to three decimal places
Explanation:
ask them out but it may not work
Answer:
x=4
Explanation:
distribute-
2x+15x-21=47
combine like terms-
17x-21=47
add 21 to both sides
17x=68
Divide 17 from both sides
x=4
<em>Balance Chemical Equation:</em>
2H3N(aq) + 3Ca(OH)2(aq) → Ca3N2(aq) + 6H2O(liq)
<em>Explanations:</em>
- According to law of mass of conservation, the chemical equation should be balanced.
- In balance chemical equations, the numbers of same or different atoms in reactants should be equal to the number of different atoms of elements of product side.