Answer: The actions that must have affected the igneous rock in order to form the sedimentary rock is that (It must have been broken down into sediments).
Explanation:
Rocks are solid structures that occurs naturally which is made up of different minerals. There are three main types of rocks, these includes:
--> METAMORPHIC ROCKS: These are the type of rocks which are formed by temperature and pressure changes inside the Earth.
--> SEDIMENTARY ROCKS: these rocks are usually formed from pre-existing rocks through the process of weathering (breaking down) of rocks.
--> IGNEOUS ROCKS: these rocks are formed when molten magma cools beneath or above the earth surface.
The actions that must have affected the igneous rock in order to form the sedimentary rock is that the igneous rocks are broken down into smaller pieces by erosion and weathering processes. Sediments which are formed accumulates at the earth surface. Over a long period of time, these sediments builds successive layers on top of one another. The sediments near the base hardens to form sedimentary rocks. This justifies the statement as a correct option (It must have been broken down into sediments).
Answer:
Just think of whats in a forest ecosystem
for example
Water
sunlight
tempreture
Physical properties- color, density, solubility.
<span>Chemical property- odor.
</span>You see, a physical property<span> is any property that can be </span>measured<span> , and a one that </span><span>describes the state of the physical system.
</span>
https://socratic.org/questions/are-properties-such-as-odor-color-density-and-solubility-physical-or-...
2 SO₃ --> 2 SO₂ + O₂
I 12 0 0
C -2x +2x +x
---------------------------------------------
E 12-2x 2x x
Since the moles of SO₂ at equilibrium is 3 mol, 2x = 3. Then, x = 1.5 mol. So, the amounts at equilibrium is:
SO₃: 12 - 2(1.5) = 9
SO₂: 2(1.5) = 3
O₂: 1.5
The formula for K basing on the stoichiometric reaction is:
K = [SO₂]²[O₂]/[SO₃]²
where the unit used is conc in mol/L.
K = [3 mol/3 L]²[1.5 mol/3 L]/[9 mol/3 L]²
<em>K = 0.0556</em>
