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Naddika [18.5K]
3 years ago
7

Rounded to the nearest thousands 6,842

Mathematics
2 answers:
mr_godi [17]3 years ago
4 0
7,000 is the answer to this. Your welcome
ValentinkaMS [17]3 years ago
4 0
7,000.
1 thousands place, rounded by the 100 place.
Below 5 round down, 5 or above round up.
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Answer:

The 98% confidence interval for the mean usage in the March quarter of 2006, in kWh, was (333.87, 416.13).

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

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Now, we have to find a value of T, which is found looking at the t table, with 29 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.98}{2} = 0.99. So we have T = 2.462

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The lower end of the interval is the sample mean subtracted by M. So it is 375 - 41.13 = 333.87 kWh

The upper end of the interval is the sample mean added to M. So it is 375 + 41.13 = 416.13 kWh

The 98% confidence interval for the mean usage in the March quarter of 2006, in kWh, was (333.87, 416.13).

6 0
3 years ago
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Answer:

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Step-by-step explanation:

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Answer:

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