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Lilit [14]
3 years ago
7

Using the digits 0 to 9, at most one time each, fill in the boxes to create a square, with one of the vertices at (2,3). Hint: 2

and 3 are already used (so they cannot be used again); not all numbers will be used.
Mathematics
1 answer:
coldgirl [10]3 years ago
3 0

Answer:

See explanation

Step-by-step explanation:

One vertex is at point (2,3).

Go 1 unit to the left and 5 units up, then the second vertex will be at the point (1,8).

Go 5 units to the right and 1 unit up, then the third vertex will be at point (6,9).

Go 1 unit to the right and 5 units down, then the fourth vertex will be at point (7,4).

Go 5 units to the left and 1 unit down to get into the vertex (2,3).

Since you always move one unit in one direction and 5 units in another direction, obtained quadrilateral will be a square.

See attached diagram for details.

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d1i1m1o1n [39]
$678.58 if u can give me brainliest thx! :)
5 0
3 years ago
Hey! Can someone check my answers?
Andrew [12]
The greatest common factor is the biggest number taken from the values.

Q1. The answer is <span>A. 5y^6
</span>
20 y^{9} +5 y^{6}= 4*5 y^{9}+5 y^{6}
Since x^{a}* x^{b}  =x^{a+b}, then x^{9}= x^{3}* x^{6}

Back to our expression:
4*5 y^{9}+5 y^{6}=4*5 y^{3}*y^{6}+5 y^{6}=4 y^{3}*5y ^{6}+  5y ^{6}*1=5 y^{6} (4y ^{3} +1)
The greatest common factor is thus 5 y^{6}


Q2. The answer is <span>D. 12xy^2
</span>
12x y^{5}+60 x^{4} y^{2} -24 x^{3} y^{3}=12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}
We will use the rule  x^{a}* x^{b} =x^{a+b} to factorise the exponents:
12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}= \\ =12x*y^{2}*y^{3}+5*12*x* x^{3} *y^{2}-2*12x* x^{2} *y*y^{2}= \\ =12xy^{2}*y^{3}+12xy^{2}*5 x^{3} -12xy^{2}*2 x^{2} y= \\ =12xy^{2}(y^{3}+5 x^{3}-2 x^{2} y)
The greatest common factor is thus 12xy^{2}
3 0
3 years ago
Do any of ya'll know the answer of this a=75.6==55?
Sergio [31]

Answer:

these are the answers you need and you'll need it anyways yw

4 0
2 years ago
Which questions are statistical questions?
Yanka [14]

Answer:

Which questions are statistical questions?

what is the number of students what is the height of each in my class?

how many servings of fruit did eat each day this month?

what is my height?

what is the highest temprature

of each month this year?

how many students from each school in this city love football?

Step-by-step explanation:

Need to include numerical values

8 0
3 years ago
Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the
kodGreya [7K]

Answer:

  • p=0.7103 (4-game series)
  • p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters  n=4, p=0.6:

P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\  i=4,5,6,7

#We find probabilities for the different values of i:

P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659

Hence, probability of the stronger team winning overall is:

=P(X=4)+P(X=5)+P(X=6)+P(X=7)\\\\=0.7103

#Define Y as the random variable for winning 2/3 games.:

P(Y=2)={1\choose 1}0.6^2=0.3600\\\\P(Y=3)={2\choose3}0.6^20.4=0.2880\\\\P(win)=0.2880+0.3600=0.6480

Hence, probability of the stronger team winning in 2 out 3 game series is 0.6480

The stronger team has a higher chance of winning in a 4-game series(0.7103>0.6480)

8 0
2 years ago
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