The equation of a cirecle with radius r and center at (h,k) is
(x-h)^2+(y-k)^2=r^2
r=10
center=(-2,-4)
(x+2)^2+(y+4)^2=10^2
(x+2)^2+(y+4)^2=100
(x,y)
sub given points (or use TI) and see if you get a true statmeent
A is on it
answer is A
Since ad, bc, and bd are integers since integers are closed under the operation of multiplication and ad-bc is an integer since integers are closed under the operation of subtraction, then (ad-bc)/bd is a rational number since it is in the form of 1 integer divided by another and the denominator is not eqaul to 0
Answer:
Yes
Step-by-step explanation:
1) Cos 300 = Cos (360 - 60) = Cos 60 {Cos 360 - theta = Cos theta}
= 1/2
Sin 300 = Sin (360 - 60) = -Sin 60 = 
3) 3π/4 = 3*180/4 = 135
Cos 135 = Cos (90 + 45) = -Cos 45 = 
Sin 135 = Sin (90 + 45) = Sin 45 = 
