Answer:
Step-by-step explanation:
y=(2x²+x)³+(x-1)/(1-x)
=(2x²+x)³+(x-1)/-(x-1)
=(2x²+x)³-1
dy/dx=3(2x²+x)(4x+1)-0
=3x(2x+1)(4x+1)
That would be 32.6 32.60 and 32.6 are exactly the same just like 1635 and 01635 are the same number
Answer:
y_c = 2 + 10*x
Step-by-step explanation:
Given:
y'' = 0
Find:
- The solution to ODE such that y(0) = 2, y'(0) = 10
Solution:
- Assuming a solution y = Ce^(mt)
So, y' = C*me^(mt)
y'' = C*m^2e^(mt)
- Back substitute into given ODE, we get:
y'' = C*m^2e^(mt) = 0
e^(mt) can not be equal to zero
- Hence, m^2 = 0
m = 0 , 0 - (repeated roots)
- The complimentary function for repeated roots is:
y_c = (C1 + C2*x)*e^(m*t)
y_c = C1 + C2*x
- Evaluate @ y(0) = 2
2 = C1 + C2*0
C1 = 2
-Evaluate @ y'(0) = 10
y'(t) = C2 = 10
Hence, y_c = 2 + 10*x
10/16 = 5/8
An equivalent fraction is:
20/32
