Answer:
0.022 mol O
Explanation:
Mg3(Si2O5)2(OH)2
We can see that 1 mol of this substance has 3 mol of Mg.
Oxygen altogether is 5*2 (from (Si2O5)2) + 2(from(OH)2) = 10 +2 = 12
So, 1 mol of this substance has 12 mol oxygen.
So, 1 mol of this substance contains 3 mol Mg and 12 mol O, or
ratio Mg : O = 3 : 12 = 1 : 4
1 mol Mg ----- 4 mol O
0.055 mol Mg ---x mol O
x = 0.055*4/1 = 0.220 mol O
430 g of AgCl would be needed to make a 4.0m solution with a volume of 0.75 L.
<h3>What is Molarity?</h3>
- The amount of a substance in a specific volume of solution is known as its molarity (M).
- The number of moles of a solute per liter of a solution is known as molarity.
<h3>Calculation of Required amount of AgCl</h3>
Remember that mol/L is the unit of molarity (M).
We can compute the necessary number of moles of solute by multiplying the concentration by the liters of solution, according to dimensional analysis.
0.75L×4.0M=3.0mol
Then, using the periodic table's molar mass for AgCl, convert from moles to grams:
3.0mol×143.321gmol=429.963g
The final step is to round to the correct significant figure, which in this case is two: 430g.
Hence, 430 g of AgCl would be needed to make a 4.0m solution with a volume of 0.75 L.
Learn more about Molarity here:
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Answer: 
is 1155 kJ
Explanation:
According to first law of thermodynamics:
=Change in internal energy
q = heat absorbed or released
w = work done or by the system
w = work done by the system=
{Work done on the system is positive as the final volume is lesser than initial volume}
w =
(1kcal=4.184 kJ)
q = +1.1 MJ = 1100 kJ (1MJ=1000kJ) {Heat absorbed by the system is positive}
Thus is 1155 kJ
When Ag+ is combined with Na2CO3, the substances formed are Ag2CO3 and Na+. In this case, Ag performs single substitution over the element Na to form another set of substances. There are other types of reactions like double displacement, decomposition, etc.
