The__ contains all the elements l, arranged according to similarities in their properties

If the solubility of AgNO3 at 40°C is 311 g per 100 g of water, what mass of this solute can be dissolved in 350 g of water at t

Mice21 [21]

Solubility<span> is a chemical property referring to the ability for a given substance, the solute, to dissolve in a solvent. It has units of grams of the substance per grams of solvent. We calculate the mass as follows:

311 g AgNO3 / 100 g water (350 g water) = 1088.5 g AgNO3

It can be rounded of to 1100 g of AgNO3. Therefore, option B is the correct answer.</span>

3 0

3 years ago

Consider the decomposition of a metal oxide to its elements, where M represents a generic metal. M 3 O 4 ( s ) − ⇀ ↽ − 3 M ( s )

Fiesta28 [93]

This is an incomplete question, here is a complete question.

Consider the decomposition of a metal oxide to its elements, where M represents a generic metal.

$M_3O_4(s)\rightleftharpoons 3M(s)+2O_2(g)$

Substance ΔG°f (kJ/mol)

M₃O₄ -9.50

M(s) 0

O₂(g) 0

What is the standard change in Gibbs energy for the reaction, as written, in the forward direction? delta G°rxn = kJ / mol.

What is the equilibrium constant of this reaction, as written, in the forward direction at 298 K?

What is the equilibrium pressure of O₂(g) over M(s) at 298 K?

Answer :

The Gibbs energy of reaction is, 9.50 kJ/mol

The equilibrium constant of this reaction is, 0.0216

The equilibrium pressure of O₂(g) is, 0.147 atm

Explanation :

The given chemical reaction is:

$PCl_3(l)\rightarrow PCl_3(g)$

First we have to calculate the Gibbs energy of reaction $(\Delta G^o)$ .

$\Delta G^o=G_f_{product}-G_f_{reactant}$

$\Delta G^o=[n_{M(s)}\times \Delta G^0_{(M(s))}+n_{O_2(g)}\times \Delta G^0_{(O_2(g))}]-[n_{M_3O_4(s)}\times \Delta G^0_{(M_3O_4(s))}]$

where,

$\Delta G^o$ = Gibbs energy of reaction = ?

n = number of moles

Now put all the given values in this expression, we get:

$\Delta G^o=[3mole\times (0kJ/mol)+2mole\times (0kJ/mol)]-[1mole\times (-9.50kJ/K.mol)]$

$\Delta G^o=9.50kJ/mol$

The Gibbs energy of reaction is, 9.50 kJ/mol

Now we have to calculate the equilibrium constant of this reaction.

The relation between the equilibrium constant and standard Gibbs free energy is:

$\Delta G^o=-RT\times \ln K$

where,

$\Delta G^o$ = standard Gibbs free energy = 9.50kJ/mol = 9500 J/mol

R = gas constant = 8.314 J/K.mol

T = temperature = 298 K

K = equilibrium constant = ?

$9500J/mol=-(8.314J/K.mol)\times (298K)\times \ln (K)$

$K=0.0216$

The equilibrium constant of this reaction is, 0.0216

Now we have to calculate the equilibrium pressure of O₂(g).

The expression of equilibrium constant is:

$K=(P_{O_2})^2$

$0.0216=(P_{O_2})^2$

$P_{O_2}=0.147atm$

The equilibrium pressure of O₂(g) is, 0.147 atm

5 0

4 years ago

What is the layer of the earth?

alukav5142 [94]

Earth can be divided into three main layers: the core, the mantle and the crust. Each of these layers can be further divided into two parts: the inner and outer core, the upper and lower mantle and the continental and oceanic crust. Both the inner and outer core are made up of mostly iron and a little bit of nickel.

4 0

3 years ago

A substance that can accept a pair of electrons to form a covalent bond is known as a lewis ____.

lesantik [10]

C. acid
have a nice day

8 0

3 years ago

If you were to observe a handful of soil, what materials would you MOST LIKELY find?

zhuklara [117]

Please Give me Brainliest

(1) A. (weathered rock and decomposed organic remains)

(2) B. (Use more land to plant crops)

(3) D. (top soil; organic matter)

(4) C. (They decompose the remains of plants and animals and add nutrients back to the soil)

(5) C. (Physical weathering)

(6) D. (The plates that formed these mountains were once under an ocean)

(7) B. (The water from her gutter pipe was washing away the soil in her flowerbed)

(8) A. (erosion)

(9) B. (Area A was completely underwater in the past)

(10) B. (Soil #2)

(11) B. (loam)

(12) D. (sediment)

Wow that took me more than an hour well Thanks And I hope I get brainliest because I worked soo hard

Hope this helps

-Sprinkles

6 0

3 years ago

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The__ contains all the elements l, arranged according to similarities in their properties​

The__ contains all the elements l, arranged according to similarities in their properties