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3 years ago

How is a solute and a solvent different

Chemistry

2 answers:

Ierofanga [76]3 years ago

8 0

Solute is substance which is dissolve in a solvent and Solvent is a substance that dissolves solute in a solution.

Mazyrski [523]3 years ago

6 0

Answer: Solute is the substance being dissolved, and solvent is the substance that the solute is dissolving in. For example, 1 g of sugar in 100 mL of water. Sugar is being solved so it is the solute, and water is what the sugar is dissolving in so it is the solvent.

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The air in a living room has a mass of 60 Kg and a specific heat of 1,020 J/kg°C. What is the change in thermal energy of the ai

arlik [135]

Answer:

Q = 306 kJ

Explanation:

Given that,

Mass, m = 60 kg

Specific heat, c = 1020 J/kg°C

The temperature changes from 20°C to 25°C.

Let Q be the change in thermal energy. The formula for the heat released is given by :

$Q=mc\Delta T$

Put all the values,

$Q=60\times 1020\times (25-20)\\\\Q=306000\ J\\\\or\\\\Q=306\ kJ$

So, 306 kJ is the change in thermal energy.

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3 years ago

How many f orbitals have the value n = 3?

dalvyx [7]

The Answer You Are Looking For Is.......

b) 3

HOPE THIS HELPS!!!!!

4 0

4 years ago

Write down the reaction of sodium hydioxide with hydrochloric acid in words and symbols.

ZanzabumX [31]

Hello!

the reaction:
sodium hydroxide + hydrochloric acid = sodium chloride

NaOH + HCl -> NaCl + H2O

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5 0

3 years ago

What is the predicted change in the boiling point of water when 1.50 g of

dezoksy [38]

Answer:

0.00735°C

Explanation:

By seeing the question, we can see the elevation in boiling point with addition of BaCl₂ in water

⠀

$\textsf {While} \: \sf {\Delta T_b} \: \textsf{expression is used} \\ \textsf {for elevation of boiling point}$

⠀

The elevation in boiling point is a phenomenon in which there is increase in boiling point in solution, when the particular type of solute is added to pure solvent.

⠀

$\sf \large \underline{The \: formula \: to \: be \: used \: in \: this \: question \: is} \\ \boxed{T_b = i \times K_b \times m}$

⠀

Where 'i' is van't hoff factor which represents the ratio of observed osmotic pressure and the value to be expected.

and 'i' is 3 (as given in the question)

⠀

'Kb' is molal boiling point constant. And it's value is 0.51°C/mol(given in question)

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'm' represent the molality of solution. Molatity is no. of moles of solution present in 1kg of solution.

⠀

To find molality, we have to divide no. of moles of solute by weight of solution

⠀

While first we need to no. of moles

$\sf \implies no. \: of \: moles = \frac{weight \: of \: solute}{molar \: mass \: of \: solute} \\ \\ \implies \sf no. \: of \: moles = \frac{1.5}{208.23} \\ \\ \sf \implies no. \: of \: moles = 0.0072$

⠀

Now, we will find molality

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$\sf \hookrightarrow molality = \frac{no.\: of \: moles}{weight \: of \: solution} \\ \\ \sf \hookrightarrow molality = \frac{0.072}{1.5} \\ \\ \sf \hookrightarrow molality = 0.048 \: mol {kg}^{ - 1}$

⠀

$\textsf{ \large{ \underline{Now substituting the required values}}}$

⠀

$\sf \longmapsto \Delta T_b = 3 \times 0.51 \times 0.0048 \\ \\ \\ \boxed{ \tt{ \longmapsto \Delta T_b =0.00735{ \degree}C}}$

⠀

Henceforth, the change in boiling point is 0.00735°C.

7 0

2 years ago

Determine the relative amounts (in terms of volume fractions) for a 15 wt% sn-85 wt% pb alloy at 100Â°c. the densities of tin an

nikdorinn [45]

Volume fraction = volume of the element / volume of the alloy

Volume = density * mass

Base: 100 grams of alloy

mass of tin = 15 grams

mass of lead = 85 grams

volume = mass / density

Volume of tin = 15g / 7.29 g/cm^3 = 2.06 cm^3

Volume of lead = 85 g / 11.27 g/cm^3 = 7.54 cm^3

Volume fraction of tin = 2.06 cm^3 / (2.06 cm^3 + 7.54 cm^3) = 0.215

Volume fraction of lead = 7.54 cm^3 / (2.06 cm^3 + 7.54 cm^3) = 0.785

As you can verify the sum of the two volume fractions equals 1: 0.215 + 0.785 = 1.000

6 0

3 years ago

How is a solute and a solvent different​

How is a solute and a solvent different