Answer: b is the answer
Step-by-step explanation:
Triangle A is the original triangle, and triangle A' is the image.
We need a pair of corresponding sides in the two triangles that are both labeled with lengths.
We see the side labeled 15.2 mm in triangle A', and we see the side labeled 3.8 mm in triangle A. These two sides are corresponding sides.
Divide the length of the side in the image by the length of the side in the original to find the scale factor.
(15.2 mm)/(3.8 mm) = 4
The scale factor is 4.
l o l
o k
s o
5x=x-9 and 4x-10y=8
lets graph that on desmos cause I'm too lazy to subsitute it .
it has one answer
Are you needing help with the last box or what are u needing help with ?
Step-by-step explanation:
Let us consider the task to find the angle between vectors ES and EJ (the first letters are taken to name the vectors).
\overrightarrow{ES} = (4;4) - (4; -3) = \overrightarrow{(0; 7)}
ES
=(4;4)−(4;−3)=
(0;7)
\overrightarrow{EJ} = (-5; -4) - (4; -3) = \overrightarrow{(-9; -1)}
EJ
=(−5;−4)−(4;−3)=
(−9;−1)
cos \alpha=\frac{\overrightarrow{ES}*\overrightarrow{EJ}}{|\overrightarrow{EJ}|*|\overrightarrow{ES}|}cosα=
∣
EJ
∣∗∣
ES
∣
ES
∗
EJ
cos(a) = (0*(-9)+7*(-1)) / (7*9.055) = -0.11043;
a = 96,34°
Solution: 96 degrees.
