A regular room has an area of 313 1/2 feet the length is 12 1/2 feet what is the width of the room
1 answer:
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You can see a graph of that function.
Here I also show you a table with some points. First take into account tha the domain is x > - 2 and that the limit of the function as x goest to - 2 is negative infinity.
x f(x)
- 1.999999999 -9
-1.99 -2
-1.9 -1
-1 0
0 0.301
1 0.477
8 1
98 2
998 3
∞ ∞
With this information and the graph you can identity which of your graphs is the right one.
Here I also show you a table with some points. First take into account tha the domain is x > - 2 and that the limit of the function as x goest to - 2 is negative infinity.
x f(x)
- 1.999999999 -9
-1.99 -2
-1.9 -1
-1 0
0 0.301
1 0.477
8 1
98 2
998 3
∞ ∞
With this information and the graph you can identity which of your graphs is the right one.
Answer:
a. length = 0.7211 ft
b. width = 0.7211 ft
c. height = 140.3846 ft
Step-by-step explanation:
This is an optimiztion with restriction problem.
We have to minimize the cost, with the restriction of the volume being equal to 72 ft3.
As the cost for the sides is constant, we know that length and width are equal.
Then, we can express the volume as:
being x: length and z: height
We can express the height in function of the length as:
Then, the cost of the box can be expressed as:
To optimize C, we derive and equal to zero
The height z is then