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Dafna1 [17]
2 years ago
10

If 5a+b=14 then a = what explain how you got it pls

Mathematics
1 answer:
Trava [24]2 years ago
8 0

Answer:

a = \frac{14 - b}{5}

Step-by-step explanation:

The rule to know and follow is:

You can add, subtract, multiply or divide by anything so long as the same thing is done to both sides of the equals sign;

5a + b = 14

If we want to get: "a = ...", then we use the rule to isolate the variable a on one side of the equation;

Firstly, we subtract b from both sides:

5a + b - b = 14 - b

5a = 14 - b

Then, divide both sides by 5:

\frac{5a}{5} = \frac{14 - b}{5} \\\\ a = \frac{14 - b}{5}

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5 0
3 years ago
Question :-
DochEvi [55]

\qquad\qquad\huge\underline{{\sf Answer}}

Let's solve ~

\qquad \sf  \dashrightarrow \:  \bigg( \dfrac{1}{ \sqrt{7 +  \sqrt{5} } }  +  \sqrt{7 +  \sqrt{5} } \bigg) {}^{2}

\qquad \sf  \dashrightarrow \:  \bigg( \dfrac{1}{ \sqrt{7 +  \sqrt{5} } } \bigg ) {}^{2}  +  \bigg( \sqrt{7 +  \sqrt{5} } \bigg) {}^{2}  + 2 \cdot \dfrac{1}{ \sqrt{7 +  \sqrt{5} } }  \cdot \sqrt{7 +  \sqrt{5} }

\qquad \sf  \dashrightarrow \: \dfrac{1}{7 +  \sqrt{5} }  + 7 +  \sqrt{5}  + 2

\qquad \sf  \dashrightarrow \: \dfrac{49 + 7 \sqrt{5} + 7 \sqrt{5} + 5 + 14 + 2 \sqrt{5}   }{7 +  \sqrt{5} }

\qquad \sf  \dashrightarrow \: \dfrac{68+ 16 \sqrt{5}    }{7 +  \sqrt{5} }

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2 years ago
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3 years ago
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3 years ago
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