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slamgirl [31]
3 years ago
10

Combine like terms to create an equivalent expression. 20(−1.5r+0.75)20(-1.5r+0.75)20(−1.5r+0.75)20, left parenthesis, minus, 1,

point, 5, r, plus, 0, point, 75, right parenthesis
Mathematics
2 answers:
Lina20 [59]3 years ago
8 0

Answer:

-30r+15

Step-by-step explanation:

I got it right on khan academy

ASHA 777 [7]3 years ago
7 0

Answer:

The combined like terms to create an equivalent expression 20(-1.5r+0.75) is -30r + 15.

Step-by-step explanation:

Consider the provided expression:

20(-1.5r+0.75)

Use the distributive property: a(b + c) = ab + bc

-30r + 15

After using distribution property there are no more like terms. Thus, -30r + 15 is the simplest form.

Hence, the combined like terms to create an equivalent expression 20(-1.5r+0.75) is -30r + 15.

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Annette [7]

Answer:

x = 12√1.5

Step-by-step explanation:

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The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l
sergij07 [2.7K]

Answer:

(a)

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(b)

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(c)

A=\frac{3\sqrt{3} }{2} x^2

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Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

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we know that

area of equilateral triangle is

=\frac{\sqrt{3} }{4} b^2

h=3x

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now, we can plug values

A=\frac{\sqrt{3} }{4} x^2

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

=6\times \frac{\sqrt{3} }{4} x^2

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(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)

V=\frac{3\sqrt{3} }{2} x^3 units^3


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